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2 years ago

Help me Here take this I

Mathematics

1 answer:

lora16 [44]2 years ago

4 0

Answer:

yesssssssssssssssssssssssss

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Add the fractions and simplify the answer 1/2+2/3

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The anawer to your question is 3/6, and simplified as 1/2.

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2 years ago

Which equation shows that 6 is a factor of 18?

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Since factors need to show that a number can be divided by another and 6*3=18, C is the answer.

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3 years ago

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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2 years ago

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Sonbull [250]

Answer:

20 days

Step-by-step explanation:

We multiply 25 by 4 to get 100, then multiply 5 by 4 to get 20.

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A line that is perpendicular to y=-4-10 passing through the point (8,11)

guapka [62]

Answer:

Step-by-step explanation:

11=4(8)+b

11=32+b

-21=b

y=4x-21

i think

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2 years ago