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Marysya12 [62]
3 years ago
14

I really need help pls help me

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0
Num. 4 no because 5t2 doesn't equal 10 …or equals7
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Write the standard form of the line that passes through the point (1,5) and is parallel to the x -axis. Include your work in you
scoray [572]

Answer:

y = 5

Step-by-step explanation:

A line parallel to the x- axis has equation

y = c

Where c is the value of the y- coordinates the line passes through

The line passes through (1, 5) with y- coordinate of 5, thus

y = 5 ← equation of line

7 0
3 years ago
Which triangle shows the incenter at point A? <br><br>The Images are placed in order A- D
vaieri [72.5K]

Answer:

B

Step-by-step explanation:

the incenter is found by constructing angle bisectors and then intersecting the three angle bisectors.

3 0
4 years ago
Read 2 more answers
2.
abruzzese [7]

Answer:

  a) 30 kangaroos in 2030

  b) decreasing 8% per year

  c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo

Step-by-step explanation:

We assume your equation is supposed to be ...

  P(t) = 76(0.92^t)

__

a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30

In the year 2030, the population of kangaroos in the province is modeled to be 30.

__

b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.

The population is decreasing by 8% each year.

__

c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.

  P(100) = 75(0.92^100) = 76(0.0002392)

  P(100) ≈ 0.0182, about 1/55th of a kangaroo

5 0
4 years ago
If a gas tank of a large truck holds 64 gallons of gas if the tank is 5/8 full how many gallons of gas is in truck
maria [59]
64/1×5/8=320/8. 320÷8=40. There is 40 gallons of gas in the truck
7 0
3 years ago
Solve 2x2 + 12x - 14 = 0 by completing the square
vovangra [49]

Answer:

<h2>x = -7 or x = 1</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\\\2x^2+12x-14=0\qquad\text{divide both sides by 2}\\\\x^2+6x-7=0\qquad\text{add 7 to both sides}\\\\x^2+2(x)(3)=7\qquad\text{add}\ 3^2=9\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=7+9\\\\(x+3)^2=16\Rightarrow x+3=\pm\sqrt{16}\\\\x+3=-4\ or\ x+3=4\qquad\text{subtract 3 from both sides}\\\\x=-7\ or\ x=1

5 0
4 years ago
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