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Answer:
take the shape of the container it is in.
Explanation:
Answer:
Between days 5 and 13 of a woman's menstrual cycle, an unfertilized egg in ovary prepares its development and maturation within the follicle, while the lining of the uterus -the endometrium- progressively enlarges.
Explanation:
Under normal conditions, a woman's menstrual cycle lasts 28 to 30 days, during which time both hormonal and physiological changes occur as part of the reproductive process.
Menstruation occurs as a result of the shedding of the endometrium, which had previously developed to facilitate the implantation of a possible pregnancy. This phase usually lasts five days and is characterized by genital bleeding.
From the fifth to the 13th day, a woman's reproductive system undergoes changes in preparation for possible fertilization and pregnancy:
- <em>The unfertilized egg</em><em> is found inside the ovarian follicle, maturing before its imminent release, under the influence of follicle-stimulating hormone (FSH). The maturation of a few follicles occurs simultaneously, but only one will reach the necessary maturity to allow the release of the egg.
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- <em>The lining of the uterus</em><em>, called the endometrium, receives signals from the hormone estradiol -produced by the mature ovarian follicle- and induces proliferation and thickening of the endometrium.</em>
Approximately on the 15th day of the menstrual cycle, the egg is released and it is the time when it can be fertilized by a sperm to produce the zygote, which will start a pregnancy in women.
Learn more:
Purpose of the menstrual cycle brainly.com/question/1483249
Answer:
The correct answer would be C. 0.60
It can be calculated with the help of Hardy-Weinberg equation i.e
p² + q² + 2pq = 1
Also, p + q = 1
- where p represents the frequency of dominant allele.
- q represents the frequency of recessive allele.
- p² represents the frequency of homozygous dominant genotype
.
- q² represents the frequency of homozygous recessive genotype
.
- 2pq represents the frequency of heterozygous genotype.
Number of homozygous dominant (YY) = 36
Number of homozygous recessive (yy) = 16
Number of heterozygous dominant (Yy) = 48
Total number of plants = 100
Now, frequency of homozygous dominant (YY) = 36/100 = 0.36
Therefore, p² = 0.36
So, p = √0.36 = 0.60
Hence, frequency of dominant allele (Y) = 0.60