Answer:
Approximately 1.9 seconds (correct to nearest tenth)
Step-by-step explanation:
Looks like the function is d = -16t^2 + 55 ( you left out the t)
The answer is the value of t when d = 0 so we have the equation:-
0 = -16t^2 + 55
16t^2 = 55
t^2 = 55/16
t = sqrt (55/16)
= 1.85 seconds
Answer:
1440 yd³
1200 yd³
Step-by-step explanation:
A local aquarium purchased a new turtle tank for their giant turtle exhibit for their giant turtle exhibit.
By using the dimensions 15yd by 12yd by 8yd and the shape of the tank is cubooid
We can determine volume by using the formula i.e
V = (Length) × (Width) × (Height),
then the volume of the tank will be
V = 15 × 12 × 8 =
V=1440 yd³.
Now , by using dimensions 15 yd by 8 yd by 10 yd
The volume will be,
V = 15 × 8 × 10 = 1200yd³
You have to take a better picture
Answer: 0.15 is equivalent to 3/20
Answer:
<h3>3 secs</h3>
Step-by-step explanation:
Given the height of the object as it drops from the observation deck expressed as;
h= -16t^2+152
To determine the the time it will take the object to be 8 feet above the valley floor, we will substitute h = 8 into the equation and calculate t as shown;
8 = -16t^2+152
subtract 8 from both sides
8-8 = -16t^2+152-8
0 = -16t^2+144
0-144 = -16t^2
-144 = -16t^2
16t^2 = 144
Divide both sides by 16;
16t^2/16 = 144/16
t^2 = 9
t = √9
t = 3seconds
Hence it will take 3 seconds for the object to be 8 feet above the valley floor
