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vodka [1.7K]
3 years ago
12

What is 33 1/3% of 24

Mathematics
2 answers:
Over [174]3 years ago
7 0
It is 8 the answer your welco
Bas_tet [7]3 years ago
3 0
33 1/3% of 24 is 7.92
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Find the mean and the median of the data set: 9, 7, 7, 4, 18 , 8, 5, 2,
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The mean and median of this date set is;
Mean: 44.25
Median: 7
Date set in order: 2,4,5,7,7,8,9,18
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Six friends will stay at a cabin in the woods this weekend. The distance to the cabin is 148.5 miles. Each person will drive one
ivolga24 [154]

Answer:

24.75/24¾

Step-by-step explanation:

148.5 ÷ 6 = 24¾ or 24.75

Answer: Each driver drove 24.75/24¾ miles

5 0
3 years ago
There are 11 students on the tennis team. The coach selects 3 of them to go to atennis clinic. In how many ways can he choose 3
Komok [63]

Answer:

165 ways

Step-by-step explanation:

Selection deals with combination

There are a total of 11 from which 3 are to be selected

        11C3 = 11!/3!(11-3)!

                 = 11!/(3!x8!)

                 =(11x10x9x8!)/(3x2x8!)

                 =11x10x9/6

                 =11x5x3 = 165 ways

                 

8 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
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