Question

Find the volume of a right circular cone that has a height of 4.5 ft and a base with a diameter of 19 ft. Round your answer to the nearest tenth of a cubic foot.

Answer 1

Answer:

Volume of the cone= $425.07feet^3$

Step-by-step explanation:

Volume of a right circular cone:

                              $\frac{1}{3} *\pi *r^2*h$

For,     height(h)= 4.5 feet

Diameter= 19 feet

Radius(r)= 19/2= 9.5 feet

As, $\pi =\frac{22}{7}=3.14$

Volume of the cone :

                               $=\frac{1}{3} *3.14*(9.5*9.5)*4.5\\\\=\frac{1}{3}*3.14* 90.25*4.5\\\\=\frac{1}{3} *3.14*406.125\\\\=\frac{1275.23}{3}\\\\ =425.07feet^3$

The volume of the cone with given dimensions is $425.07feet^3$