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Semenov [28]
3 years ago
7

Find the volume of a right circular cone that has a height of 4.5 ft and a base with a diameter of 19 ft. Round your answer to t

he nearest tenth of a cubic foot.
Mathematics
1 answer:
guapka [62]3 years ago
4 0

Answer:

Volume of the cone= 425.07feet^3

Step-by-step explanation:

Volume of a right circular cone:

                              \frac{1}{3} *\pi *r^2*h

For,     height(h)= 4.5 feet

Diameter= 19 feet

Radius(r)= 19/2= 9.5 feet

As, \pi =\frac{22}{7}=3.14

Volume of the cone :

                               =\frac{1}{3} *3.14*(9.5*9.5)*4.5\\\\=\frac{1}{3}*3.14* 90.25*4.5\\\\=\frac{1}{3} *3.14*406.125\\\\=\frac{1275.23}{3}\\\\ =425.07feet^3

The volume of the cone with given dimensions is 425.07feet^3

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