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3 years ago

How do you correctly graph a system of inequalities

Mathematics

1 answer:

Olin [163]3 years ago

8 0

Answer:

Step-by-step explanation:

Rearrange the equation so "y" is on the left and everything else on the right.

Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).

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Please help I don't understand

Bond [772]

Answer:

mx+b

Step-by-step explanation:

3 0

3 years ago

you are making beaded bracelets for your for your friends. you want to use 30 beads for each bracelet want to use no more than 1

Softa [21]

30(x)<=145 and yes she would be able to make 4 bracelets because 30 x 4 = 120 and that is less than 145

5 0

3 years ago

Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x

djverab [1.8K]

I'll assume the ODE is

$y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}$

Solve the homogeneous ODE,

$y'' - 3y' + 2y = 0$

The characteristic equation

$r^2 - 3r + 2 = (r - 1) (r - 2) = 0$

has roots at $r=1$ and $r=2$ . Then the characteristic solution is

$y = C_1 e^x + C_2 e^{2x}$

For nonhomogeneous ODE (1),

$y'' - 3y' + 2y = e^x$

consider the ansatz particular solution

$y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x$

Substituting this into (1) gives

$a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1$

For the nonhomogeneous ODE (2),

$y'' - 3y' + 2y = e^{2x}$

take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

Substitute (2) into the ODE to get

$b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1$

Lastly, for the nonhomogeneous ODE (3)

$y'' - 3y' + 2y = e^{-x}$

take the ansatz

$y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}$

and solve for $c$ .

$ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16$

Then the general solution to the ODE is

$\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}$

6 0

1 year ago

In triangle APS, A = 14.3, P = 19.2, S = 72.4. Find angle p to the nearest tenth.

slamgirl [31]

Answer:

C.) 65 degrees

Step-by-step explanation: I put 72.6 and got it wrong.

3 0

3 years ago

2. The line that passes through the points (-6, p)

Kobotan [32]

Answer: -26=p

Explanation: The slope formula is m=(y2-y1)/(x2-x1).

Thus, we have 6=(2-p)/(-10-(-6)).

Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.

5 0

3 years ago