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Eva8 [605]
3 years ago
9

Help asap The graphs below have the same shape. What is the equation of the red graph? G(x) = O A. G(x) = 2 - 4 B. G(X) = (5 - x

)4 O C. G(X) = 5 - 4 O D. G(x) = (2 - x)4
no links​

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

G(x) = 5 - x⁴

Step-by-step explanation:

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Nata [24]
Y=4x-13

that is the line
4 0
4 years ago
Plsss I need help!!!
mrs_skeptik [129]

Answer:

POSSIBLY  2

Step-by-step explanation: wasnt the best at math but i hope u do good

3 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
What is the shape of the cross-section formed when a plane containing line AC and line EH intersects this cube? What is the area
velikii [3]

Answer:

Cross section is a rectangle.

Area of cross section = 16 sqrt(2) = 22.63 sq. units (to 2 decimals)

Step-by-step explanation:

Given a cube.

top face ABCD is parallel and congruent to bottom face EFGH  ........(1)

justified by the properties of cubes

Sides AE and CH are perpendicular to faces ABCD and EFGH ..........(2)

justified by the properties of cubes

Diagonals AC and EH are congruent ......................(3)

justified by (1), congruent top and bottom faces  

Consider cross-section ACHE

AC is congruent and parallel to  EH   (1) & (3)

EA & HC are perpendicular to AC      (2)

Therefore the quadrilateral ACHE is a rectangle.

Length of diagonal AC = sqrt(4^2+4^2) = 4 sqrt(2)  ..........pythagoras theorem

AE = CH = DG = 4      properties of cube, all sides equal

Area of ACHE = 4* 4sqrt(2) = 16 sqrt(2) = 22.63 sq. units

4 0
3 years ago
What is the x? please answer!
zzz [600]

Answer:

x = 2

Step-by-step explanation:

1. distribute 9 in 9(x+1)

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2. subtract x from the right side to isolate x onto one side

8x + 9 = 25

3. subtract 9 from the left side

8x = 16

4. divide both sides by 8 to get x alone

x = 2

8 0
3 years ago
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