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Iteru [2.4K]
3 years ago
6

How much would something cost if it was $20 but was 1/5 percent off??

Mathematics
2 answers:
muminat3 years ago
7 0
$16
Cuz 1/5 of 20 is 4.
It is 4 dollars off.
QveST [7]3 years ago
6 0
4$ would be the cost of the item
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The radius of the moon is approximately 1,350,000 m. What is the radius in kilometers? (1 km=1000m)
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I believe it is 1,350 but i am not completely sure

Step-by-step explanation:

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Giselle has $16.25 in her wallet and needs to get to her uncle���s house 8 miles away. a taxi costs $2.50 for the first mile and
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Veronica owns stocks worth 11,200. She owes 4,500 on her student loans and 800 on her credit cards. She owes 6,000 on her car th
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$300

Step-by-step explanation:

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wolverine [178]
B I hope it helps for you
3 0
2 years ago
A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c
Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

n = 2228.6

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0
3 years ago
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