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Kryger [21]
3 years ago
5

PLEAS HURRY I HAVE NO TIME LEFT

Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

no you scam me if I see what is promises I will help you

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The common demoninator of 10 can be 6. 11 is 12 and 12 is just five.
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3 years ago
What is twice 2^30? write using exponents
8090 [49]
2(2^{30})=2^1*2^{30}=2^{1+30}=2^{31}
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3 years ago
DOES ANYONE KNOW THE ANSWER???
Greeley [361]
First one is the answer
7 0
3 years ago
What is the product of the two matrices? Fill in the missing elements of the resulting matrix.​
olganol [36]

The product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Here we are given the 2 matrices as follows-

\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]

= \left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]

= \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Thus, the product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Learn more about matrices here-

brainly.com/question/13595915

#SPJ1

3 0
1 year ago
Plz help with the question below
gregori [183]

5\sqrt[3]{x} +4=44\\\\ 5\sqrt[3]{x} =44-4 \\\\ 5\sqrt[3]{x} =40 \\\\ \sqrt[3]{x} =\frac{40}{5}  \\\\ \sqrt[3]{x} =8 \\ \\ x=8^3\\ \\ \boxed{ x=512}

6 0
3 years ago
Read 2 more answers
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