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3 years ago

2³ x 6 ÷ 12 = 4 + (5² - 2³) =

Mathematics

2 answers:

Oliga [24]3 years ago

5 0

Answer:

12 ÷12 = 1

Step-by-step explanation:

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Leno4ka [110]3 years ago

4 0

Answer:

The first one is 4

The second on is 21

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What is the order of the steps to solve for x in the equation 3x - 6x - 7 = 29?

Anna35 [415]

Answer:

3x - 6x - 7 = 29 Given

-----------------------------------

3x - 6x -7 = 29

+ 7 + 7 Addition property of equality

3x - 6x = 36

--------------------------------------------------------------

3x - 6x = 36

(3x + -6x) = 36 Combine like terms

-3x = 36

--------------------------------------------------------------

-3x = 36

(-3x = 36)/ -3 Division property of equality

x = -12

Step-by-step explanation:

I tried to seperate the steps so you can go through them. First you had to add on both sides to take out the like terms, then combine the 3x and the -6x to make -3x (easier to look at and divide), and finally divide to find X. the end product using X cannot be a negative because its a filler space for a real number.

Hope this helps :)

8 0

4 years ago

When x=1/2, what is the value of 8x-3/x

Viefleur [7K]

8x - 3/x

x = 1/2

(8 • 1/2) - 3/0.5

4 - 1.5

2.5

6 0

4 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$