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3 years ago

13

If -x = 20, then x = ?

2 answers:

katrin2010 [14]3 years ago

7 0

Answer:

$- x = 20 \\ so \: x \: will \: be \: = - 20$

Hope it helps!

bogdanovich [222]3 years ago

5 0

Answer: x = -20

Step-by-step explanation:

Question: If -x = 20, then x = ?

Multiply both sides of the equation by -1

(-1)(-x) = (-1)(20)

Simplify (remember that multiplying two negative numbers equals a positive number)

x = -20

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OLga [1]

This is hard bro google it or u could ask the questions sepretly it mskes it easy

6 0

4 years ago

Together, teammates Pedro and Ricky got 2673 base hits last season. Pedro had 277 more hits than Ricky. How many hits did each

ioda

Answer:

Pedro got 1520 base hits and Ricky got 1243.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of base hits that Pedro got.

y is the number of base hits that Ricky got.

Pedro and Ricky got 2673 base hits last season.

This means that $x + y = 2763$

Pedro had 277 more hits than Ricky.

This means that $x = y + 277$

Replacing in the first equation

$x + y = 2763$

$y + 277 + y = 2763$

$2y = 2486$

$y = \frac{2486}{2}$

$y = 1243$

$x = y + 277 = 1243 + 277 = 1520$

Pedro got 1520 base hits and Ricky got 1243.

4 0

3 years ago

Write the following quotient in the form a+bi.<br> -7i/2-7i

Helga [31]

Answer:

$\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}$

Step-by-step explanation:

$\text{Use}\\\\i=\sqrt{-1}\to i^2=-1\\\\(a-b)(a+b)=a^2-b^2\to(a-bi)(a+bi)=a^2+b^2\\\\\text{distributive property}\ a(b+c)=ab+ac\\---------------------\\\\\dfrac{-7i}{2-7i}=\dfrac{-7i}{2-7i}\cdot\dfrac{2+7i}{2+7i}=\dfrac{-7i(2+7i)}{2^2+7^2}=\dfrac{(-7i)(2)+(-7i)(7i)}{4+49}\\\\=\dfrac{-14i-49i^2}{53}=\dfrac{-14i-49(-1)}{53}=\dfrac{-14i+49}{53}\\\\=\dfrac{49}{53}-\dfrac{14}{53}i$

8 0

3 years ago

Read 2 more answers

The difference of a number and 12 is 30.determin the number

ElenaW [278]

42 because 42-12=30 hope dis helped my guy

3 0

3 years ago

Read 2 more answers

Given GHI G (4,-3), H (-4,2), and I (2,4), find the perpendicular bisector of HI in standard form.

Olin [163]

Answer:

$3x+y=0$

Step-by-step explanation:

step 1

Find the slope of segment HI

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

H (-4,2), and I (2,4)

substitute the given points

$m=\frac{4-2}{2+4}$

$m=\frac{2}{6}$

simplify

$m=\frac{1}{3}$

step 2

Find the slope of the perpendicular line to segment HI

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=\frac{1}{3}$

so

$m_2=-3$

step 3

Find the midpoint segment HI

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

H (-4,2), and I (2,4)

substitute

$M(\frac{-4+2}{2},\frac{2+4}{2})$

$M(-1,3)$

step 4

we know that

The perpendicular bisector of HI is a line perpendicular to HI that passes though the midpoint of HI

Find the equation of the perpendicular bisector of HI in point slope form

$y-y1=m(x-x1)$

we have

$m=-3$

$M(-1,3)$

substitute

$y-3=-3(x+1)$

step 5

Convert to slope intercept form

$y=mx+b$

Isolate the variable y

$y-3=-3x-3$

$y=-3x-3+3$

$y=-3x$

step 6

Convert to standard form

$Ax+By=C$

where

A is a positive integer

B and C are integers

$y=-3x$

Adds 3x both sides

$3x+y=0$

see the attached figure to better understand the problem

3 0

4 years ago