All categories

2 years ago

Consider the diagram.

Mathematics

1 answer:

Eddi Din [679]2 years ago

7 0

Answer:its 9

Step-by-step explanation: got it right on edge

You might be interested in

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

fomenos

Answer:

C. The graph of G(x) is the graph of F(x) flipped over the y-axis and compressed vertically.

Step-by-step explanation:

The negative in front of the 2 made the function flip over the y-axis. While the 2, compressed the function a little, making it so the function touched 2, vertically.

7 0

2 years ago

Can you solve 27,28,39,30,31,32,33,34?

kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

$27. \: \: \frac{ {x}^{ - 1} }{ {x}^{ - 8} } \\ \frac{ {x}^{8} }{ {x}^{1} } \\ {x}^{8 - 1} = {x}^{7} \\$

$28. \: \: \: \frac{ {52x}^{6} }{ {13x}^{ - 7} } \\ \frac{ {52x}^{6} {x}^{7} }{13} \\ {4x}^{6 + 7} = {4x}^{13}$

$29. \: \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\ {f}^{( - 3) +2 + ( - 3) } \\ {f}^{ - 4} \\ \frac{1}{ {f}^{4} } \\$

$30. \: \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\ \frac{ {x}^{9} }{ {x}^{4} } \\ {x}^{9 - 4} = {x}^{5}$

$31. \: \: \frac{ {24x}^{6} }{ {12x}^{ - 8} } \\ \frac{ {24x}^{6} {x}^{8} }{12} \\ {2x}^{6 + 8} = {2x}^{14} \\$

$32. \: \: \frac{ {3x}^{2} {y}^{ - 3} }{ {12x}^{6} {y}^{3} } \\ \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3} {y}^{3} } \\ \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} } \\ \frac{ {x}^{ - 4} }{ {4y}^{6} } \\ \frac{1}{ {4y}^{6} {x}^{4} } = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }$

$33. \: \: {( {2x}^{3} {y}^{ - 3}) }^{ - 2} \\ {2x}^{3 \times - 2} {y}^{ - 3 \times - 2} \\ {2x}^{ - 6} {y}^{6} \\ \frac{ {2y}^{6} }{ {x}^{6} } \\ {( \frac{2y}{x} )}^{6} \\$

4 0

2 years ago

What is 32\6 - 4 5\7

givi [52]

32/6 - 4 5/7

32/6 - 20/7

52/21 = 2 10/21 or 2.47

5 0

3 years ago

Pls help. i never understood this rule.

Dimas [21]

L'Hopital rule only applies to indeterminate cases of 0/0 or ∞/∞ or 0*0 or ∞ * ∞.

and you'd need to make the expression a rational, where the numerator and denominator gives you 0/0 or ∞/∞, then you apply L'Hopital.

the only candidate there is

$\bf \lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\implies \lim\limits_{x\to \infty}\cfrac{2(\infty)^2-1}{3(\infty)+1}\implies \cfrac{\infty}{\infty}
\\\\\\
\textit{so we can use L'Hopital by instead using the derivatives}
\\\\\\
\lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}\cfrac{4x}{3}\implies \cfrac{4(\infty)}{3}\implies \infty$

8 0

3 years ago

Camman help me hehehehehheheheh

nordsb [41]

On this one I am just going to do the problems and not write "Answer: whatever" at the end. It's your job to read and understand what I wrote and extract the answer from it.

$2 \frac 3 4 \text{ cups} \times \dfrac{1 \textrm{ dumpling}}{ \frac 3 {16} \textrm{ cup}} = \frac{11}{4} \times \frac{16}{3} = \frac{44}{3} = 14 \frac 2 3 \textrm{ dumplings}$

We're asked for how many whole dumplings, so that's 14.

$x + 8.63 = 11.001$

$x = 11.001 - 8.63 = 2.371$

$\text{area} = \textrm{base} \times \textrm{height} = 5 \frac 1 4 \times 4 \frac 1 5 = \frac {21}{4} \times \frac{21}{5} = \frac{441}{20} \textrm{ sq in} = 22 \frac 1 {20} \textrm{ sq in}$

6 0

2 years ago