Ask question

Ask question

All categories

3 years ago

12

Rlly needing some help asap thanks

2 answers:

shepuryov [24]3 years ago

6 0

It's actually quite simple. =)

Since you want to highlight sequences that correspond to, where three coins at least land on tails, you want to highlight any of these following sequences:
HTTT
TTTH
TTHT
THTT

This is because, they each have three coins in them, that landed on tails.
Let me know if this wasn't what you were looking for or need additional help. =)

olga nikolaevna [1]3 years ago

4 0

Its a 50/50 chance because a coin only has 2 side

You might be interested in

NEED HELP ASAP PLZZZZ:(

Crazy boy [7]

Answer:

I cant see the questions?

Step-by-step explanation:

4 0

3 years ago

Evaluate: |18|<br> A:1/18<br> B:-1/-18<br> C:-18<br> D18

masya89 [10]

Answer will be D. Absolute value can never be negative.

4 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

3 years ago

Find the distance between the given points: (2, -2) and (-4, 7)

sasho [114]

Answer:

$3\sqrt{13}$

Step-by-step explanation:

Hi there!

We want to find the distance between the points (2, -2) and (-4, 7).

To do that, we can use the distance formula.

The distance formula is given as $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything needed to find the distance, but let's label the values of the points to avoid any confusion

$x_1=2\\y_1=-2\\x_2=-4\\y_2=7$

Now substitute those values into the formula and solve

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\sqrt{(-4-2)^2+(7--2)^2}$

Simplify

$\sqrt{(-4-2)^2+(7+2)^2}$

$\sqrt{(-6)^2+(9)^2}$

Square the numbers under the radical

$\sqrt{36+81}$

Add the numbers under the radical together

$\sqrt{117}$

Simplify the square root

$3\sqrt{13}$

Hope this helps!

6 0

3 years ago

What is the answer to this fraction problem 4/5 - 8/15?

Marianna [84]

Is the answer to your question 4/15?

5 0

3 years ago

Read 2 more answers