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Triss [41]
4 years ago
12

Keith plans on eating 1 1/4 cups of tuna per day for five days. How much tuna does he need? Is 4 cans enough? Canned tuna/meat:

4 cans = 5 & 3/5 cups.
Mathematics
2 answers:
antiseptic1488 [7]4 years ago
8 0
He has too much for 4 cans. He has 5 3/5 cups.
Stells [14]4 years ago
5 0
Not it would not be enough it will have to 6.5 cans
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Write an equation of a line that passes through (-3, 5) and (-7, 5).
timurjin [86]

Answer:

y=5

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

   = ( 5-5)/( -7 - -3)

   = ( 5-5) / ( -7+3)

  = 0/-4

The slope is 0

This means it is a horizontal line

Horizontal lines are in the form

y =

The y coordinate is 5

y=5

7 0
3 years ago
Mr. jones bought 4 concert tickets for $252. what was the price per ticket.
Diano4ka-milaya [45]
It is 63 dollars per ticket 
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Write an equation that models the sequence 400, 200, 100, 50, ...
Julli [10]
You're starting at 400. Each time you're cutting in half. 

So the common ratio is 1/2 which means the equation is

\Large y = 400(1/2)^{x-1}

which is in the geometric sequence format. So the answer is choice D
3 0
3 years ago
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In △ABC AL is an angle bisector (L∈ BC ). Point M∈ AB so that LM=AM=BM. Find the angles in △ABC, if AC=2AL.
Diano4ka-milaya [45]

If AM=BM, then point M is a middle point of side AB.

1. Consider triangle AML. You know that AM=ML, then this triangle is isosceles and AL is its base. The angles adjacent to the base of isosceles triangle are conruent, this means that \angle MAK\cong \angle AML.

2. Consider lines ML and AC. The angle bisector AL is transversal. Since alternate interior angles \angle MAK\cong \angle AML, you have that lines ML and AC are parallel. This means that ML is a middle line of triangle and 2ML=AC. Also you know that AC=2AL. This gives you that ML=AL. Now ML=AL and ML=AM gives you that triangle AML is equilateral.

3. In equilateral triangle AML all angles are congruent and have measures 60°. Thus, m∠AML=m∠MLA=m∠LAM=60°.

4. AL is angle bisector, then m∠MAL=m∠LAC=60° and m∠BAC=m∠MAL+m∠LAC=120°.

5. Consider ΔBML, it is isosceles, because BM=ML and m∠BML=180°-m∠AML=180°-60°=120°. Then,

m\angle MBL=m\angle MLB=\dfrac{180^{\circ}-120^{\circ}}{2}=30^{\circ}.

6. Consider triangle ABC. In this triangle m∠A=120°, m∠B=30°, then

m∠C=180°-m∠A-m∠B=180°-120°-30°=30°.

Answer: m∠A=120°, m∠B=m∠C=30°.

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