Question

a study of the effects of exercis used rats bred to have high or low capacity for exercise. The 8 high capacity rats had mean blood pressure 89 mm Hg and variance 81; the 8 low-capacity rats had mean blood pressure 105 mm Hg with variance 169. What is the value of the two-sample t statistic for comapring the two population means

Answer 1

Answer:

$t=-2.86$

Step-by-step explanation:

From the question we are told that:

Sample 1 $n_1=8$

Sample 1 mean blood pressure $\=x_1=89mmHg$

Sample 1 variance $\sigma_1=81$

Sample 2 $n_2=8$

Sample 2 mean blood pressure $\=x_2=105mmHg$

Sample 2 variance $\sigma_2=169$

Generally the equation for the test of statistic is mathematically given by

$t=\frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_2}{n_1}+\frac{\sigma_2}{n_2} } }$

$t=\frac{89-105}{\sqrt{\frac{81}{8}+\frac{169}{8} } }$

$t=-2.86$

therefore the samples test for comparing the two population means

$t=-2.86$