The weather outside was very abnormal. The temperature started out at 22°C in the morning and went to -3°C at noon. It stayed at
that temperature for six hours and then dropped 4°C. How far below the freezing point (0°C) was the temperature at 6 p.m.? *
1 answer:
Answer:
your answr would be 16c
Step-by-step explanation:
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Answer:
Step-by-step explanation:
× =
=
~~~~~~~~~~~~~
× = (3²)² × = =
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Thus each angle has a measure of 108° degrees.
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Both points are on the graph.
Multiply both sides by 8
5/8g × 8 = 40× 8
5g = 320
Divide both sides by 5
5g/5 = 320/5
G = 64
It’s A it’s honestly a simple equation just can’t explain it in typing