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2 years ago

Write 600 as a product of it's primse factors

Mathematics

1 answer:

givi [52]2 years ago

8 0

Answer:

2*2*2*3*5*5

2^3 *3* 5^2

Step-by-step explanation:

600 = 60*10

These are not prime so keep going, breaking 60 and 10 down

= 6*10 * 5*2

6 and 10 are not prime so keep going ( 5 and 2 are prime)

= 3*2 * 5*2 * 5*2

All of the numbers are prime, so we normally write them in order from smallest to largest

2*2*2*3*5*5

We can write with exponents

2^3 *3* 5^2

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The answer is 12.3 percent!

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3 years ago

Perform the indicated operation. x/2+y/3-z/4

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3 years ago

Read 2 more answers

Someone please help me

GalinKa [24]

Answer:

A. 9 sqrt 2

Explanation:

Plug in hypotenuse and given side into
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3 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

3 years ago

A farmer has 1,800 feet of fencing and wants to fence off a rectangular field that borders a straight river. he needs no fence a

astra-53 [7]

There are 2 short sides x and 1 long side y.

x+x+y=1,800
2x+y=1,800
y=1,800-2x

The area of the rectangle is A=x(1,800-x).

A is a function with variable x. Moreover it is a quadratic (second degree) function.

The graph of the function is a parabola which opens downwards, because the signs of the leading coefficients of the factors, multiply to minus:

(x)(-x)=-x^2.

This means that the highest point of the parabola, is its vertex V(h,k), so the function takes its largest value for x=h.

The roots of A=x(1,800-x) are x=0 and x=1,800, thus the x coordinate of the vertex, must be the midpoint of 0 and 1,800, that is 900.

Answer:

A=x(1,800-x)

largest area is when x=900

4 0

3 years ago

Read 2 more answers