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DanielleElmas [232]
3 years ago
10

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

onger than the base edge. The height of the pyramid can be represented as The of an equilateral triangle with length x is (x ^ 2 * sqrt(3))/4 * u * n * i * t * s ^ 2 times the The area of the hexagon base is area of the equilateral triangle . The volume of the pyramid is x ^ 3 * sqrt(3) * u * n * i * t * s ^ 3
Mathematics
1 answer:
eduard3 years ago
8 0

1.) 3x

2.) area

3.) six

4.) 3/2

:)

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Guys pls help me!!!!!
KiRa [710]
I think c, 36 cubic feet. I’m not sure though
8 0
3 years ago
Simplify square root of 2 over cube root of 2.
Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

\sqrt[n]{x}  =  {x}^{ \frac{1}{n} }

So you can rewrite the given fraction as

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }  =  {2}^{ \frac{1}{2} -  \frac{1}{3}  }

Since

\frac{1}{2}  -  \frac{1}{3}  =  \frac{3}{6}  -  \frac{2}{6}  =  \frac{1}{6}

the answer is

{2}^{ \frac{1}{6} }  \: or \:  \sqrt[6]{2}

3 0
3 years ago
Read 2 more answers
Kate is going to purchase a coat for $38, pants for $45, and 2 pairs of shoes for $34 each. if she has $180 to spend how much mo
likoan [24]
She would have 20 dollars left over. take the amount of money she has then add up all of the cost of the stuff she will buy then subtract.
5 0
3 years ago
How many times larger is 3*10^8 than 5*10^6
Alex777 [14]
60 times larger.
Hope I helped!!!
8 0
3 years ago
(3x+2)∧2=9 how do i solve this in the square root property
Irina18 [472]
(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5

x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}
 

6 0
3 years ago
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