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levacccp [35]
3 years ago
6

Jamison Company uses the reciprocal services method to allocate support department costs and has gathered the following informat

ion: ​ Janitorial Department Usage Cafeteria 50% Cutting 10% Assembly 40% Cafeteria Department Usage Janitorial 20% Cutting 60% Assembly 20% Janitorial Department costs are $450,000. Cafeteria Department costs are $250,000. What are the correct equations to represent (a) the total Janitorial (J) costs, (b) the total Cafeteria (C) costs, and (c) the rewritten equation substituting C into J?
Business
1 answer:
Daniel [21]3 years ago
4 0

Answer:

a)J = 450,000 +(20% * C)

b)C =250000+ (50%*J )

c)J = 450000 + {20%* [250000+(50%*J)}

Explanation:

a)J = 450,000 +(20% * C)

This represent the total cost of Janitorial Department due to the fact that 450000 is a direct cost of janitorial department plus 20% of total cost of Cafeteria department allocated to Janitorial department.

b)C =250,000+ (50%*J )

This represent the total cost of cafeteria Department due to the fact that 250,000 is a direct cost of cafeteria department plus 50% of total cost of Janitorial department allocated to cafeteria department.

c)

Substituting the value of C determined in part b in part a

J = 450,000 + {20%* [250,000+(50%*J)}

Therefore in place of C in equation 1 ,the value of c determined in equation 2 is thereby substituted .

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A leftward shift in the long-run aggregate supply curve is most likely going to cause which of the following?
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Which of the following government
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C. bonds

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Bond P is a premium bond with a coupon rate of 9 percent. Bond D has a coupon rate of 5 percent and is currently selling at a di
Firdavs [7]

Answer:

a) 7% as their market price will adjsut to give the same yield as the market

b) bond P = -10.17

 bonds D  = 10.07

Explanation:

we have to calcualte the price variation of the bonds from now (10 years to maturity) to next year (9 years)

Bond P

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 90.000

time 10

rate 0.07

90 \times \frac{1-(1+0.07)^{-10} }{0.07} = PV\\

PV $632.1223

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   10.00

rate  0.07

\frac{1000}{(1 + 0.07)^{10} } = PV  

PV   508.35

PV c $632.1223

PV m  $508.3493

Total $1,140.4716

then, at time = 9

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 90.000

time 9

rate 0.07

90 \times \frac{1-(1+0.07)^{-9} }{0.07} = PV\\

PV $586.3709

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   9.00

rate  0.07

\frac{1000}{(1 + 0.07)^{9} } = PV  

PV   543.93

PV c $586.3709

PV m  $543.9337

Total $1,130.3046

Capital loss: 1,130.30 - 1,140.47 = -10.17

We repeat the process for bond D

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 50.000

time 10

rate 0.07

50 \times \frac{1-(1+0.07)^{-10} }{0.07} = PV\\

PV $351.1791

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   10.00

rate  0.07

\frac{1000}{(1 + 0.07)^{10} } = PV  

PV   508.35

PV c $351.1791

PV m  $508.3493

Total $859.5284

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 50.000

time 9

rate 0.07

50 \times \frac{1-(1+0.07)^{-9} }{0.07} = PV\\

PV $325.7616

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity   1,000.00

time   9.00

rate  0.07

\frac{1000}{(1 + 0.07)^{9} } = PV  

PV   543.93

PV c $325.7616

PV m  $543.9337

Total $869.6954

Capital gain: 869.70 - 859.53 = 10.07

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3 years ago
The cob Douglas production function is given by Q(K,L)=AK^1.4*L^1.6
Alexeev081 [22]

Part a) The Cob Douglas production function is given as:

Q(K,L)=AK^{1.4} L^ {1.6 } .

To show that this function is homogeneous with degree 3, we introduce be a parameter, t.

Q(tK,tL)=A(tK)^{1.4} (tL)^ {1.6 } .

Using properties of exponents, we on tinder:

Q(tK,tL)=At^{1.4}K^{1.4} t^ {1.6 }L^ {1.6 } .

This implies that:

Q(tK,tL)=t^{1.4} \times t^ {1.6 }(AK^{1.4} L^ {1.6 } )

Q(tK,tL)=t^{1.4 + 1.6}(AK^{1.4} L^ {1.6 } )

Simplify the exponent of t to get;

Q(tK,tL)=t^{3}(AK^{1.4} L^ {1.6 } )

Hence the function is homogeneous with degree, 3

Part b) To verify Euler's Theorem, we must show that:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L}=3AK^{1.4}L^{1.6}

Verifying from the left:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =K(1.4AK^{0.4} L^{1.6}) + L(1.6AK^{1.4} L^{0.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =1.4(AK^{1.4} L^{1.6}) + 1.6(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =(1.4 +  1.6)(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =3(AK^{1.4} L^{1.6})

Q•E•D

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