F(x) = 2^x; h(x) = x^3 + x + 8
Table
x f(x) = 2^x h(x) = x^3 + x + 8
0 2^0 = 1 0 + 0 + 8 = 8
1 2^1 = 2 1^3 + 1 + 8 = 10
2 2^2 = 4 2^3 + 2 + 8 = 8 + 2 + 8 = 18
3 2^3 = 8 3^3 + 3 + 8 = 27 + 3 + 8 = 38
4 2^2 = 16 4^3 + 4 + 8 = 76
10 2^10 = 1024 10^3 +10 + 8 = 1018
9 2^9 = 512 9^3 + 9 + 8 = 729 + 9 + 8 = 746
Answer: an approximate value of 10
Answer:
true
Step-by-step explanation:
Answer:
1/7
Step-by-step explanation:
Answer:
x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
5(x + 2) = 6x + 3x - 14
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Addition] Combine like terms: 5(x + 2) = 9x - 14
- [Distributive Property] Distribute 5: 5x + 10 = 9x - 14
- [Subtraction Property of Equality] Subtract 9x on both sides: -4x + 10 = -14
- [Subtraction Property of Equality] Subtract 10 on both sides: -4x = -24
- [Division Property of Equality] Divide -4 on both sides: x = 6
8 - 3 = 5 Slope formula numerator
2 - 0 = 2 Slope formula denominator
5/2 = 2.5
