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Vinil7 [7]
3 years ago
5

The graph of f(x) = |x-h| + k contains the blunts (-6,-2) and (0,-2). The graph has a vertex at (h,-5). Describe how to find the

value of h. Then, explain how this value translates the graph of the parent function.
Mathematics
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

1

Step-by-step explanation:

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What is the value of the power a if 5 to the power of a is equal to 1/125
padilas [110]

First of all, you should know/notice that

125=5^3

You should also know how negative exponents work:

a^{-m}=\dfrac{1}{a^m}

So, if you wanted

5^x=125

the answer would be x=3, but since you want 125 to be at the denominator, the answer is x=-3:

5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}

7 0
3 years ago
A chandelier was marked up 150% from an original purchase cost of $92. Yesterday, Jayce sold the chandelier, earning a 20% commi
tatuchka [14]

Answer:

92 * 1.5 = 138

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Step-by-step explanation:

4 0
3 years ago
!!!!HELP NEEDED!!!!
Svetllana [295]

It is true that the product of two consecutive even integers are always one less than the square of their average.

<u>Step-by-step explanation</u>:

Let the two consecutive odd integers be 1 and 3.

  • The product of 1 and 3 is (1\times3)=3
  • The average of 1 and 3 is (1+3)/2 =4/2 = 2
  • The square of their average is (2)² = 4

∴ The product 3 is one less than the square of their average 4.

Let the two consecutive even integers be 2 and 4.

  • The product of 2 and 4 is (2\times4)=8
  • The average of 2 and 4 is (2+4)/2 =6/2 = 3
  • The square of their average is (3)² = 9

∴ The product 8 is one less than the square of their average 9.

Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.

4 0
3 years ago
Rearrange the quadration equation so that it is equal to 0. Then factor the equation.
Alenkasestr [34]
What is the equation?
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3 years ago
The points P and Q in the following figure define the line segment (PQ⎯⎯⎯⎯⎯) P Q . The steps involved in using a compass to cons
kenny6666 [7]
You haven't provided the steps.

mathisfun.com/geometry/construct-linebisect.html

Here is a useful link to the correct steps. The instructions may not be exactly the same but I think you can do it.
3 0
3 years ago
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