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3 years ago

11

9.A. (3, 6)B. (20, –4)C. (10, –1)D. (–1, 8)

1 answer:

crimeas [40]3 years ago

7 0

Answer:

(10, –1)

Step-by-step explanation:

[1]XXXX3y=−12x+2

[2]XXXXy=−x+9

While it is not technically necessary, I find it easier to clear the fractions before actually beginning; so multiplying [1] by 2

[3]XXXX6y=−x+4

Substituting (from [2]) (−x+9) for y in [3]

[4]XXXX6(−x+9)=−x+4

Simplifying

[5]XXXX−6x+54=−x+4

[6]XXXX5x=50

[7]XXXXx=10

Substituting (from [7]) 10 for x in [2]

[8]XXXXy=−10+9=−1

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Salsk061 [2.6K]

Answer:

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4 years ago

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cestrela7 [59]

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3 years ago

The number of people, N, that Denis can invite to his party is dependent on the amount of money, x, in dollars,

gulaghasi [49]

Answer:

N(h) = 2h + 6

Step-by-step explanation:

A model of the number of people that Denis can invite to his party:

N(x) = x/25.............(1)

Where x = amount of money saved

Amount of money saved can be modeled by the equation:

M(h) = 50h + 150...........(2)

In the above model, h = number of overtime hours

M(h) = amount of money saved = x

Therefore equation (1) can be re - written as:

N(x) = M(h)/25.................................(3)

Substituting equation (2) into equation (3)

$N(h) = \frac{50h + 150}{25} \\N(h) = \frac{50h}{25} + \frac{150}{25} \\N(h) = 2h + 6$

Find an explicit expression that models the number of people that Denis can invite to his party if he worked h overtime hours this week can be expressed as:

N(h) = 2h + 6

7 0

4 years ago

Find the gradient of the line joining (-1,9) and (3,5)

givi [52]

$\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}$

<em>Find the gradient of the line joining (-1,9) and (3,5)</em>

<em /> $\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}$

Use the slope formula:-

$\boxed{\frac{y_2-y_1}{x_2-x_1}}$

Replace the letters with the numbers:-

$\boxed{\frac{5-9}{3-(-1)}}$

$\circ$ On simplification,

$\boxed{\frac{-4}{3+1}}$

$\circ$ On further simplification,

$\boxed{\frac{-4}{4}}$

$\circ\sf{SLOPE=-1}$

<h3>Good luck with your studies.</h3>

$\rule{300}{1}$

5 0

2 years ago

Tony was Challenged to a half-court shooting competition. For every half-court shot that he makes, he will earn 20 points. For e

Mkey [24]

Answer:

Tony make 4 half-court shots and misses 16 half-court shots.

Step-by-step explanation:

Given:

Points earned for every successful, half-court shots = $20$

Points deducted for missing the shots = $5$ or $-5$

Total number of shots in the game = $20$

Final points earned by Tony = $0$

According to the question:

Let the number of successful half-court shot be $x$

And the number of shots missed be $20-x$

So,

In terms of points we can re-write it as:

⇒ $20(x)-5(20-x) =0$

⇒ $20x-100+5x=0$

⇒ $25x-100=0$

⇒ $25x-100+100=100$

⇒ $25x=100$

⇒ $\frac{25x}{25} =\frac{100}{25}$

⇒ $x=\frac{100}{25}$

⇒ $x=4$

Tony make 'x' shots that is 4 and the number of shot he missed is (20-x) =(20-4)=16

6 0

4 years ago