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masha68 [24]
2 years ago
11

Convert 5 feet 4 inches to centimeters. (2.54 cm = 1 inch) * PLEASE HELPPPP

Mathematics
1 answer:
hjlf2 years ago
7 0

Answer:

162.56 cm

Step-by-step explanation:

also you can use a conversion calculator for faster results too

can i get brainliest plz

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What is the value of x? Show all of your work.Round your answer to the nearest tenth.
Mashutka [201]

Answer:

x=20.6\ in

Step-by-step explanation:

we know that

Applying the Pythagoras Theorem

41.2^{2} =35.7^{2} +x^{2}

solver for x

x^{2}=41.2^{2}-35.7^{2}

x^{2}=422.95

x=20.6\ in

8 0
3 years ago
Can someone help me with all this?? i really dont get it ​
olga nikolaevna [1]

Answer:

A=78

B=102

C=78

Step-by-step explanation:

A= a and 102 are on a straight line so they add up to 180. 180-102=78. The same goes for C

B= the vertical angle for 102, or the same thing with a and c, just flipped around

8 0
3 years ago
Graph the line with slope 3 and y-intercept -8.
Rama09 [41]
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3 0
3 years ago
Which table best classifies the following numbers as rational and irrational?
g100num [7]
The rational negative 6 over 5.,3.5,0 point 5 bar,. square root of 4.
Hope this helps :)
4 0
3 years ago
A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
3 years ago
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