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Archy [21]
3 years ago
5

2.3 Code Practice: Question 1

Computers and Technology
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

a=int(input("Enter a numerator: "))

b=int(input("Enter a divisor: "))

quotient=a/b

remainder=a%b

print("Quotient is: " + str(int(quotient)))

print("Remainder is: " + str(int(remainder)))

Explanation:

Hope this helps lovely :)

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Complete the getNumOfCharacters() method, which returns the number of characters in the user's string. We encourage you to use a
photoshop1234 [79]

Answer:

The Java code is given below with appropriate comments

Explanation:

//Program

//Import the necessary libraries

import java.util.Scanner;

//Define the class

public class CountStringCharacters

{

//Start the main method

public static void main(String[] args)

{

//Prompt the user to enter the input line

Scanner scan = new Scanner(System.in);

System.out.println("Enter a sentence or phrase: ");

String s = scan.nextLine();

 

//Take the number of characters and keep the count

int numOfCharacters = getNumOfCharacters(s);

System.out.println("You entered: "+s);

System.out.println("Number of characters: "+numOfCharacters);

 

//Call the method outputWithoutWhitespace

outputWithoutWhitespace(s);

}

//The method getNumOfCharacters

public static int getNumOfCharacters(String s)

{

int numOfCharCount = 0;

for(int i=0; i<s.length();i++)

{

numOfCharCount++;

}

return numOfCharCount;

}

//Definition of the method outputWithoutspace

public static void outputWithoutWhitespace(String s)

{

String str = "";

for(int i=0; i<s.length();i++)

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char ch = s.charAt(i);

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System.out.println("String with no whitespace: "+str);

}

}

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Read 2 more answers
) how many bits are used for host number on the child network (subnet) , b) how many usable addresses can exist on this child ne
vovikov84 [41]

Answer:

Machine’s IP=126.127.85.170, Machine’s Netmask=/27, Parent’s Netmask=255.255.240.0 .

a) Machine's Netmask = /27 : therefore no. of remaining bits for hosts =32-27 = 5 bits.

b) No. of usable addresses in the child network = 25 -2 = 32-2 =30 [Since first(network ID of the machine) and last ip (broadcast address of the machine ) addresses are not used ]

c) first usable address is on this child network (subnet) =

First, find out the network id of machine can be found out by doing bitwise AND machine's IP and Machine's subnet mask :

01111110. 01111111.01010101.10101010 (IP)

11111111. 11111111 .11111111 .11100000 (Subnet Mask)

01111110. 01111111. 01010101.10100000 (Network ID )

first usable address is on this child network (subnet) :   01111110. 01111111. 01010101.10100001

: 126.127.85.161

d) what the last usable address is on this child network (subnet) :  01111110. 01111111. 01010101.10111110

: 126.127.85.190

e) what the child network’s (subnet's) broadcast address is :

In the directed broadcast address , all the host bits are 1. Therefore, broadcast address :

01111110. 01111111. 01010101.10111111 (126.127.85.191)

f) what the child network's (subnet's) network number is : Network ID has already been calcuulated in part c .

01111110. 01111111. 01010101.10100000 (126.127.85.160)

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