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shepuryov [24]
3 years ago
5

What is the average for a human piens A 2.inc B 4inc C 10 inc D 1 feet

Biology
2 answers:
VMariaS [17]3 years ago
7 0

Answer:

the average size is 4 inch. I think

ikadub [295]3 years ago
4 0

Answer:

B. 4in

Explanation:

I'm not sure, and I don't want to look it up.

But that's the most reasonable.

2 is too small, 10 in is to big and 1 foot is to big.

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Can someone answer this?
polet [3.4K]

1a. The parent is homozygote dominant and homozygote recessive where red(R) is the dominant trait and white(r) is the recessive trait. The genotype of the parents should be:

homozygote dominant= RR

homozygote recessive= rr


1b. To find the possible offspring, you need to know the possible gametes from each parent and make a punnet square with it.

RR

possible gamete= 100% R


rr

possible gamete= 100% r


punnet square of the offspring:

    R  

r   Rr

The answer is 100% Rr


1c. Red flower is a phenotype. This because red is dominant, phenotype will be expressed when the gene is homozygote dominant or heterozygote. The offspring from the cross is 100% heterozygote, so the chance for red flower would be 100% too.


1d. White flower is a phenotype. This because white is recessive, phenotype will be expressed when the gene is homozygote recessive only. The offspring from the cross is 100% heterozygote which mean 0% chance for homozygote recessive. So the chance for white flower would be 0%.



2.
The purple stem(P) is dominant of green stem(p) and red fruit(R) is dominant over yellow fruit(r).
Both parents for the crossing is heterozygote for both traits, so the phenotype and genotype would be green stem and yellow fruit(Pp Rr)

PpRr possible gamete: PR, Pr, pR, pr
The punnet square should be 4x4 with the possible gamete above. It is hard to draw in here but the phenotype should be at 9:3:3:1 ratio

3a. Brown allele is dominant to all other traits. That means you need at least 1 brown allele to make the cat has brown eyes phenotype. The possible phenotype would be:
C^{W}C^{W}
C^{W}C^{N}
C^{W}C^{Y}
C^{W}C^{B}
The total is 4 possible genotype

3b. The grey allele is dominant to blue, but recessive to brown and green. Grey eye phenotype would need at least one grey allele, without the brown or green allele. The possible genotype would be:
C^{Y}C^{Y}
C^{Y}C^{B}
The total is 2 possible genotype

3c. Green eye cat will need at least green allele without brown allele.  The punnet square should be:

    W     Y
N WN  YN
Y  WY  YY
The phenotype of the offspring is WN(brown), WY(brown), YN(green), YY(grey). So, the chance for green eye would be 1/4 = 25%
8 0
4 years ago
What is so unusual about solid water being less dense than liquid form
mrs_skeptik [129]
That it is the same substance and yet has a different density?
8 0
3 years ago
Which of the following evidence statements would be supported by the two models
Fiesta28 [93]

sugars and amino acids are made of the same elements except amino acids also cointan nitrogen.

6 0
4 years ago
If all fours plants were watered daily but placed in a closet receiving no sunlight what process would NOT occur
lora16 [44]

Answer: photosynthesis

Explanation:

3 0
3 years ago
_____ form scar tissue and surround foreign material in the body.
nekit [7.7K]

Answer:

<u>Fibroblasts</u><u> </u> form scar tissue and surround foreign material in the body.

7 0
3 years ago
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