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Alisiya [41]
2 years ago
9

The eastbound train travels 10 miles per hour faster than the westbound train. After 2 hours, they are 232 miles apart. At what

speeds are the two trains traveling?
Mathematics
1 answer:
patriot [66]2 years ago
8 0

Answer:

48,58

Step-by-step explanation:

Let The speed of the west bound train be x

Let the east bound train be x+10

The speeds can be calculated as follows

2(2x+10)= 232

4x + 40= 232

4x= 232-40

4x= 192

x= 192/4

= 48

Hence the speedof the west bound train is 48

The speed of the east bound train is 48+10

= 58

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denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
Is this wrong?? If so whats the answer?
mart [117]

Answer:2/12

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4 0
1 year ago
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Bogdan [553]

Answer:

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Step-by-step explanation:

I dont know which variable you're supposed to solve for. But here's how i got the answer above:

Divide each term in a(4-x)=3x+b by 4-x

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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