Step-by-step explanation:
5:6
is your answer.
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It is
If you have a slope (which is before the x) then it’s a linear equation

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
it means that u have to ratios that are equivalent in weight meaning 3:3 = 1 and so is 6:6=1
I would say it's 3/8 of a cup because if you multiply 3/4 by 2 it would be 6/8. It's the same amount but just a different measurement. Now just take 3 away from 6/8 and you have 3/8 which is half of 3/4.