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riadik2000 [5.3K]
3 years ago
14

Georgie believes that a special juice will increase the productivity of his workers. He creates two groups, two workers per grou

p. Both groups are assigned the same task, stapling a set of papers. Group A is given the special juice to drink while they work. Group B is not given the special juice. After an hour, Georgie counts how many stacks of papers each group has stapled. Group A stapled 1,320 stacks while Group B stapled 2,200 stacks. Georgie concluded that the juice was not effective in improving productivity.
How would you improve Georgie's experimental design to produce a more valid conclusion?

Select one:
a. Georgie should use more than two people per group.
b. Georgie should also consider employee attendance as a variable.
c. Both groups should take the juice, just a different amount of it.
d. Georgie should not do this experiment as it has no practical implications.
Biology
2 answers:
nasty-shy [4]3 years ago
8 0
A- Georgie should have use more than two people per group.
vovikov84 [41]3 years ago
7 0

Answer:

♡ hi angel ♡

-- your answer is a

~Clara ✧・゚: *

Explanation:

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AnnyKZ [126]

Answer: I don't have the picture you're looking at, but I can try to give you some clues to help you out.

Prophase is where the chromatids enter the cell and the chromosomes attach to the spindle fibers in the cell.

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Telophase: is where the sister chromatids go to opposite sides of the cell right before they split

Anaphase is when they finally split and are now classified as two different cells. One parent cell and one daughter cell.

I hope this helps you to solve your problem!

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6 0
2 years ago
There are 100 cats in a population that follows hardy-weinberg conditions. 4 cats display a recessive white coat color. how many
mr Goodwill [35]

We know that Hardy-Weinberg conditions include the following equations:


p^{2}+2pq+ q^{2}=1


where p+q=1


And where p = dominant, and q = recessive; this means that p^{2} is equal to the homozygous dominant, 2pq is the heterozygous, and q^{2} is the homozygous recessive .


So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of \frac{4}{100} or 0.04. Let that equal our q^{2} value.


So when we solve for q, we get:


q^{2}=0.04

q=\sqrt{0.04} =0.2


Now that we have our q value, we can use the other equation to find p:


p+q=1


p+0.2=1


p=0.8


So then we can solve for our heterozygous population:


2pq=2(0.8)(0.2)=0.32


This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:


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So now we know that there are 32 heterozygous cats in the population.

8 0
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effector

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What is digested in the small intestine including the nutrients, substance, enzyme and final product of the thing being digested
inn [45]

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