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Reil [10]
2 years ago
13

What is the domain and range of {(1,3),(−4,0),(3,1),(0,4),(2,3)}

Mathematics
1 answer:
Kamila [148]2 years ago
7 0

Answer:

domain (1,-4,3,0,2)

range (3,0,1,4,3)

Step-by-step explanation:

domain means the first word of bracket

and range means the remaining

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15 students ask to visit a college admissions counselor. Each visit includes one student. In how many ways can 10 time slots be
ValentinkaMS [17]
There are ten time slots for these appointments. For the first time slot, there are 15 different students that can fill the slot. Next appointment, there are only 14 possible students since we already saw one. This goes on and on, 15 x 14 x 13... for 10 different time slots. 


<span>15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 = 10,897,286,400 
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Can anyone help me with this please
Vikentia [17]

Answer:

1. 3

2. 1

3. 9

4. 30

Step-by-step explanation:

1. 2*(18/12) = 3

2. 3*(5/15) = 1

3. 4*(45/20) = 9

4. 21*(10/7) = 30

4 0
2 years ago
Read 2 more answers
the moon takes 29 1/2 days to pass through its phases. explain why lunar calendar would be inaccurate.
denpristay [2]
Theluner calender would be inaccurate because it doesnt shouw the full 29 and a half days as the moon turns through its phases

8 0
3 years ago
Read 2 more answers
A plane has an airspeed of 134 km divided by h. It is flying on a bearing of 78 degrees while there is a 21 km divided by h wind
ANEK [815]

Answer:

Ground speed = 131.25 km/h

Bearing = 92.68º

Step-by-step explanation:

If we imagine a triangle to depict the question with one side 134 km/h at an angle of 78º to the right of vertical (the plane's speed vector).

At the end, we have a line 21 km/h at an angle of 180 (from north), a vertical down from the end of the plane's vector. This vertex is angle B

This makes a triangle with the interior angle B of 78º.

The 3rd side is the ground speed which we can find using the Cosine rule:

b² = a² + c² - 2•a•c•cos(78)

b² = 134² + 21² - 2•134•21•cos(78)

b² = 17226.873

b = 131.25 km/h

The true course bearing" is the ground track. Thus;

Using the Sine rule to find angle A, we have;

(sin(A))/34= sin(78)/b

Thus,

sin(A) = (34 x sin(78))/131.25

sin(A) = 0.2534

A = sin^(-1)0.2534

A = 14.68º

Ground track = A + 78 = 14.68 + 78 = 92.68º

8 0
3 years ago
Which is greater 11/2 or 4\8
Nikitich [7]
11/2 is greater than 4/8
11/2=5.5
4/8=1/2=0.5
8 0
2 years ago
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