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scoundrel [369]
2 years ago
8

HELP WITH GEOMETRY TEST QUESTION PLEASE

Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

so the sides would have to be equal for all sides

2x-3=3x-8    -3=x-8    x=5

x-12, 4x-1, neither, or both?

2x-3=x-12       x-3=-12      x=-9

4x-1=3x-8      x-1=-8      x=-7

2x-3=4x-1      -3=2x-1    -4 = 2x    x=-2

3x-8=x-12       2x-8=-12     2x=-4    x=-2

So the answer is neither or C

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Please help me with this
SVEN [57.7K]
You can use 1 of 2 methods to solve this problem. You can either solve it traditionally or by just looking at it (you don't necessarily need to convert it to scientific notation to find the answer).

{METHOD 1}- Traditional Method

Scientific Notation is just another way of writing REALLY BIG or REALLY SMALL numbers in a simplified manor

Let's take 232,000,000 for instance

First you want to find your decimal number. Your decimal number has to be Greater than 1 and less than 10.

In this case your decimal number will be 2.32

Then let's could how many decimal places are to the RIGHT of 2.32
Keep in mind that if the number is very small you have to count the decimal places to the LEFT


{METHOD 2}

If you look at 232,000,000 and 2,320,000,000 you can tell that 2,320,000,000 is longer just by looking at it, so you can determine that ....

232,000,000 = 2.32E8
2,320,000,000=2.32E9

Using the same method you can solve the last two.

0.00000431 is a larger number than 0.000000000000431. So you can then determine that.....

0.00000431= 4.31E-6
0.000000000000431=4.31E-13

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3 years ago
If m(x) =x+5/x-1 and n(x) = x - 3, which function has the same domain as (mºn)(x)?
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We have

M(X) = (X + 5)/(X - 1)

N(X) = X - 3

So,

M(N(X)) =  [(X - 3) + 5]/[(X - 3) - 1]

<h3>M(N(X)) =  [X + 2]/[X - 4]</h3>

The M(N(X)) domain will be:

D = {X / X ≠ 4}

4 ∉ to the M(N(X)) domain, otherwise we would have a/0, which is not possible (a denominator with zero). An equivalent function would be

H(X) = 1/(X - 4)

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The rate of change is gonna be 0
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3 years ago
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mina [271]

Step-by-step explanation:

the rhombus is both rectangle and square

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2 years ago
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(5x+7)(8x+7) = 0<br>Find the two possible values.​
NeTakaya

(5x + 7)(8x + 7) \\  \\ 5x + 7 = 0 \\  \\ 5x =  - 7 \\  \\ x =  \frac{ - 7}{5}  \\  \\ 8x + 7 = 0 \\  \\ 8x =  - 7 \\  \\ x =  \frac{ - 7}{8} .

the values of x are -7/5 and -7/8 .

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