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Papessa [141]
2 years ago
12

PLEASE HELP!!!!!!!

Mathematics
1 answer:
crimeas [40]2 years ago
7 0

Answer:

24.5

Step-by-step explanation:

❤❤❤❤❤❤❤

plz give brainliest

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6x+x^2 standard form​
Anna11 [10]

Answer:45

Step-by-step explanation:

8 0
3 years ago
Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
Spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 62.1
Marta_Voda [28]
Caution:  you need to use the same units of measurement throughout.  If the spring stretches by 21 cm when a 135 newton object is attached, then you must ask for the mass (in newtons) of a fish that would stretch the spring by 62.1 cm.

We will need to assume that the spring is not stretched at all if and when no object is attached to the spring.

Write the ratio

                21.0 cm        135 newtons
               ------------- = --------------------
                 62.1 cm               x

Solve this for x.  This x value represents the mass of a fish that would stretch the spring by 62.1 cm.  You can cancel "cm" in the equation above:

21.0      135 newtons
------ = --------------------
62.1               x

Then 21.0x = (62.1)(135 newtons).  Divide both sides of this equation by 21.0 to solve it for x.
7 0
3 years ago
Read 2 more answers
A33 =<br> 1<br> 6<br> 8<br> Please help.
Firdavs [7]

Answer:

Need more information

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the area? (IXL)
Zina [86]

Answer:

45 square meters

Step-by-step explanation:

we know that

The area of trapezoid is equal to

A=\frac{1}{2}(b1+b2)h

where

b1 and b2 are the parallel bases

h is the height of trapezoid (perpendicular distance between the parallel bases)

we have

b1=6\ m\\b2=9\ m\\h=6\ m

substitute

A=\frac{1}{2}(6+9)6

A=45\ m^2

3 0
3 years ago
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