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3 years ago

Guyss help plss i need serious answer I'm buriéd with work plss beg :(

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

6 0

Answer:

solution given:

CE=2×2=4[base side is double to the line of mid point]

AB=15/2=7.5[b is a mid point]

m<AEC=75°[ corresponding angle]

given:

BD=x+1

CE=x+10

we have

2BD=CE

2(x+1)=x+10

2x+2=x+10

2x-x=10-2

x=8

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Ill mark you brainlist plz help if you put something random I will report you! I

Kisachek [45]

Answer:

x = 0

y = 2

Step-by-step explanation:

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3 years ago

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A cylinder has diameter of 4ft and a height of 9ft. Explain whether halving the diameter has the same effect on the surface area

elena55 [62]

Answer:

See Below

Step-by-step explanation:

The surface area of cylinder is given by the formula:

$SA=2\pi r^2 + 2\pi r h$

Where

r is radius ( diameter is 4, so radius is 4/2 = 2)

h is height ( h = 9)

Lets find original surface are:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (9)\\SA=8\pi +36\pi\\SA=44\pi$

<u>Halving diameter:</u>

diameter would be 4/2 = 2, so radius would be 2/2 = 1

So, SA would be:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (1)^2 + 2\pi (1) (9)\\SA=2\pi +18\pi\\SA=20\pi$

<u>Halving height:</u>

Height is 9, halving would make it 9/2 = 4.5

Now, calculating new SA:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (4.5)\\SA=8\pi + 18\pi\\SA= 26\pi$

Original SA is $44\pi$ ,

Halving diameter makes it $20\pi$

Halving height makes it $26\pi$

So, halving diameter does not have same effect as halving height.

5 0

3 years ago

Someone help and makes sure the answer is right please :)

oksian1 [2.3K]

Answer:

x=6

Step-by-step explanation:

Since the two lines are parallel, the angles are congruent to each other.

-4+14x=80

14x=84

x=6

Hope this helps!

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3 years ago

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Blizzard [7]

The interview was 11.3 minutes.

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3 years ago

Which graph represents the function f(x)=x4+4x3−12x2−32x+64?

sp2606 [1]

$f(x)=x^4+4x^3-12x^2-32x+64$

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first graph

x intercepts of first graph is -4 and 2

Plug in -4 for x in f(x) and check whether we get 0

$f(x)=x^4+4x^3-12x^2-32x+64$

$f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0$

Now plug in 2 for x and check

$f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0$

So -4 and 2 are the x intercepts that satisfies f(x)

Hence first option is the graph of $f(x)=x^4+4x^3-12x^2-32x+64$

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3 years ago

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Guyss help plss i need serious answer I'm buriéd with work plss beg :(​

Guyss help plss i need serious answer I'm buriéd with work plss beg :(