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olga_2 [115]
2 years ago
14

Find the value of x to the nearest tenth. 46° Х 20°

Mathematics
2 answers:
Scilla [17]2 years ago
8 0

Answer:

the answer of the question is that it will be 60 to the nearest tenth

GREYUIT [131]2 years ago
4 0

Answer:

x = 14.7

Step-by-step explanation:

law of sines:

sin 20°/7 = sin 46°/x

x ·sin(20°) = 7 ·sin(46°)

x = 7 ·sin(46°) / sin(20°)

x = 14.722

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A notebook costs $2.39 at Walmart. If the tax rate is 7%, what is the total cost at the register?
shusha [124]
$2.39 is 100%
$x is 7%

2.39 x 7 = 16,73
16,73/100 = 0,17
the total cost is $2,56
5 0
3 years ago
Landry earned $2,300 over the summer and decided to invest it in an account that earns 4% annual compound interest. If Landry do
solniwko [45]

Answer:

Landry will have $5039.58

Step-by-step explanation:

compound interest formula: amount = p(1 + \frac{r}{n})^{nt}

p= principal ($2,300)

r= interest rate as a decimal (4% = 0.04)

n= number of times the principal is compounded per year (annually = once per year so 1 time per year)

t= time in years (20 years)

new equation: amount = 2300(1+\frac{0.04}{1} )^{1*20}

That equation equals $2,739.58 which you add to the principal.

$2,739.58 + $2,300 = $5039.58

hope this helps :) the equations aren't showing up right :(

6 0
3 years ago
Read 2 more answers
Is t = 9 a solution to the inequality below?<br> 8&gt;t<br> Please hurry and explain!
dexar [7]

Answer:

no

Step-by-step explanation:

its 7

7 0
2 years ago
House 1 2 3 4 5 6 7 8
bekas [8.4K]

Answer:

Median

Step-by-step explanation:

Since the data has an outlier (12,985), mean is not the best average.

This data set does not have a modal value

Therefore the best option is Median

4 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0
3 years ago
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