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zysi [14]
3 years ago
8

A motor boat and a raft start traveling downstream. After 1 hour, the boat turns around and travels back until it reaches the ra

ft. a What amount of time does it take the boat to reach the raft after it turns around?
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Complete question is;

A motor boat and a raft start traveling downstream. After 1 hour, the boat turns around and travels back until it reaches the raft. If the distance traveled by the raft is 6 miles, what is the speed of the current?

Answer:

1 hour

Step-by-step explanation:

The speed downstream will be given by; (v + u)

The speed when traveling back upstream is; (v - u)

We are told time it took to travel downstream = 1 hr

Let's denote time to travel upstream as t.

Now, distance = speed × time

Distance travelled downstream in an hour = (v - u)1

Distance it takes to get back to the raft is; (v - u)t

Thus;

(v + u)1 - (v - u)t = 6

(v + u) - (v - u)t = 6 - - - (eq 1)

Now, since the distance covered by the raft is 6 miles, it also did it in (1 + t) hours. Thus, the speed = u miles/hr

Thus, distance is;

u(1 + t) = 6 - - - (eq 2)

Putting u(1 + t) for 6 in eq 1,we have;

(v + u) - (v - u)t = u(1 + t)

v + u - vt + ut = u + ut

u and ut cancel out to give;

v - vt = 0

v = vt

t = v/v

t = 1 hour

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4 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
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Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

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1. Substitute the function f(x) into x in g(x)

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3. There are 350 people in an office building. A local deli randomly surveyed people in the building to determine the average am
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The least representative of the population is sample 1

Step-by-step explanation:

The mean is ∑fx/∑f

∑fx = 30 + 25 + 10 + 25 + 10 = 100

∑f = 5

Mean = 100/5 = 20

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10, 10, 25, 25, 30

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The mean is ∑fx/∑f

∑fx = 5 + 60 + 10 + 30 + 50 = 155

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Mean = 155/5 = 31

For the median, we arrange the data in increasing order;

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The median = the middle number = 30

(b) Sample 1 range =$30 -$10 = $20

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Sample 1 has the least spread

Sample 1 standard deviation = 9.354

Sample 2 standard deviation =24.083

Sample 1 has the least deviations from the mean

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Therefore sample 1 align with the third sample

The least representative of the population is sample 1 with ∑fx = 100.

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