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elena55 [62]
2 years ago
5

Their win percentage was 40, then how many matches did they play in all!

Mathematics
1 answer:
Neko [114]2 years ago
3 0

Answer:

14400

Step-by-step explanation:

X - X × 75%=3600

X - X × \frac{75}{100} = 3600

X - \frac{3X}{4} = 3600

\frac{4X-3X}{4} = 3600

\frac{X}{4} = 3600

X = 3600 × 4

X = 14400

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Twenty-five percent of the customers entering a grocery store between 5 P.M. and 7 P.M. use an express checkout. Consider five r
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Step-by-step explanation:

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3 years ago
A 45 foot ladders leaning up against a building. The base of the latter is 20 feet away from the building. What is the angle of
Tatiana [17]

Answer:

The angle of elevation to the top of the building is 63.61 degrees

Step-by-step explanation:

Here, we want to calculate angle of elevation to the top of the building.

For this, we need a triangle

Please check for this in the attachment.

From the diagram, we are to calculate the angle theta.

To do this, we use trigonometric identities.

Looking at what we have, we have the hypotenuse and the adjacent.

So the trigonometric identity to use is the cosine

Mathematically Cosine theta = adjacent/hypotenuse

Thus, Cos theta = 20/45

Cos theta = 0.444444444444444

Theta = Arc cos(0.444444444444444)

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3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

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There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

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ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

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There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

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