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xeze [42]
2 years ago
13

The measure of ZPQS is 180°. The measure of ZRQS is 30°.

Mathematics
1 answer:
Ray Of Light [21]2 years ago
4 0
The measure of ZPQR is C. 150°
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Tell whether the ordered pair is a solution to the equation. Please show how you solved it.
Alina [70]

Answer:

The ordered pair is a solution to the equation

Step-by-step explanation:

Plug the ordered pair into the equation as (x,y):

y = -x + 8

4 = -4 + 8

4 = 4

Since both sides are equal to each other, then the ordered pair is a solution to the equation.

6 0
2 years ago
Read 2 more answers
Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87​ +2 54​ )− 21​
lora16 [44]

Answer:

12\dfrac{7}{40}

Step-by-step explanation:

The given expression is

\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}

We need to find the simplified form of the given expression.

It can be rewritten as

\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}

Combine integers and fractions separately.

(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})

Taking LCM we get

11+\dfrac{35+32-20}{40}

11+\dfrac{47}{40}

In can be written as

11+\dfrac{40+7}{40}

11+1+\dfrac{7}{40}

12+\dfrac{7}{40}

12\dfrac{7}{40}

Therefore, the expression 12\dfrac{7}{40} is equivalent to the given expression.

5 0
3 years ago
Find the value of x.
dimaraw [331]

Answer:

2\sqrt{77}

Step-by-step explanation:

Use the Pythagorean theorem. a^{2} +b^{2}=c^{2}

a and b are the two side lengths

c is the hypotenuse (value across from the right angle)

Plug in the values that you are given.

a^{2} +4^{2} =18^{2}

Solve for x

x^{2} =18^{2} -4^{2}

x^{2} =308

x=\sqrt{308}

x=2\sqrt{77}

5 0
2 years ago
Help I’m timed I’ll mark u brainliesttt
Zigmanuir [339]
It would be 5sqrt2

a^2 + b^2 = c^2
5^2 + 5^2 = c^2
25 + 25 = c^2
50 = c^2
c = sqrt 50
c = 5sqrt2
4 0
3 years ago
What method would you choose to solve the equation 2x^2-7=9
Margaret [11]
Here is one way to solve for x.

Step 1)  2x^2-7=9

Step 2)  2x^2-7+7=9+7

Step 3)  2x^2=16

Step 4)  (2x^2)/2=16/2

Step 5)  x^2=8

Step 6)  sqrt(x^2)=sqrt(8)

Step 7)  |x|=sqrt(8)

Step 8)  x=sqrt(8) or x=-sqrt(8)

-------------------------------------

Below are explanations/reasons to each of the steps above.

Step 1) Original equation

Step 2) Add 7 to both sides

Step 3) Combine like terms

Step 4) Divide both sides by 2

Step 5) Simplify

Step 6) Apply the square root to both sides. The notation "sqrt" is shorthand for "square root"

Step 7) Use the rule that sqrt(x^2) = |x| for all real numbers x

Step 8) Use the rule that if |x| = k then x = k or x = -k for some fixed number k.

-------------------------------------

The two solutions are
x = sqrt(8) or x = -sqrt(8)

3 0
3 years ago
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