Given: 3x + y = 1<br> Solve for y.<br> A. y=-3x + 1<br> B. y=-3x - 1<br> C. y= 3x

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

Use the confidence interval to find the margin of error and the sample mean (0.118,0.220)

malfutka [58]

Answer:

μ = 0.169

ME = 0.051

Step-by-step explanation:

The confidence interval is:

CI = μ ± ME

So the mean is the middle of the confidence interval, and the margin of error is half the difference.

μ = (0.118 + 0.220) / 2 = 0.169

ME = (0.220 − 0.118) / 2 = 0.051

5 0

4 years ago

Whats 3 to the power of zero? is it just 3

zepelin [54]

Answer:

$3^0 = 1$

Step-by-step explanation:

$a^0 =1 ,~~ a \neq 0$

5 0

2 years ago

7/4x^2 -2 = - 0.05x + 4

nata0808 [166]

Answer:

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

Step-by-step explanation:

Step One: Convert

49/16x^2-2=-0.05x+4

Step Two: Multiply Both Sides by 80

245x^2-160=-4x+320

Step Three: Move everything to the left

245x^2+4x-480=0

Final Step: Quadratic Formula

$x1=\frac{-2-2\sqrt{29401} }{245} x2=\frac{-2+2\sqrt{29401} }{245}$

6 0

3 years ago

Can anyone help me plz and I need the person to explain it for me

lions [1.4K]

Answer:

1 cm = 100 mi

28.9/1=28.9

28.9 x 100 = 2890 miles distance

2890 / 65 miles per hour = 44.4615 hours to drive

44.461/24 hours in a day = 1.85 rounded up is 2 days

About two days

If you have any questions you can ask

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Given: 3x + y = 1 Solve for y. A. y=-3x + 1 B. y=-3x - 1 C. y= 3x - 1