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Makovka662 [10]
3 years ago
8

I NEED HELP PLZ

Mathematics
1 answer:
Ratling [72]3 years ago
8 0
D fed ifjk vs cjsioxhdjducjskvuhdkfuxhxiufuc
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Across which Axis was point H reflected?
Vedmedyk [2.9K]

Answer:

X - axis

Step-by-step explanation:

H(9, - 1) \rightarrow H'(9, 1)

Since in the above reflection x coordinate remains the same and y-coordinate changes from 1 to - 1, hence point H is reflecting across X - axis.

4 0
3 years ago
Acrosonic's production department estimates that the total cost (in dollars) incurred in manufacturing x ElectroStat speaker sys
il63 [147K]

Answer:

a)  P(x)=-0.042x^2+530x-18000

b)  P'(x)=-0.084x+530

c)

P'(4000)=194

P'(9500)=-268

Step-by-step explanation:

a)

We know that Revenue is our total income and cost is our total cost. Thus, profit is what's left after cost is subtracted from Income (revenue). Thus, we can say:

P(x) = R(x) - C(x)

Finding Profit Function (P(x)):

P(x) = R(x) - C(x)\\P(x) = -0.042x^2+800x-(270x+18000)\\P(x)=-0.042x^2+800x-270x-18000\\P(x)=-0.042x^2+530x-18000

This is the profit function.

b)

The marginal profit is the profit earned when ONE ADDITIONAL UNIT of the product is sold. This is basically the rate of change of profit per unit. We find this by finding the DERIVATIVE of the Profit Function.

Remember the power rule for differentiation shown below:

\frac{d}{dx}(x^n)=nx^{n-1}

Now, we differentiate the profit function to get the marginal profit function (P'):

P(x)=-0.042x^2+530x-18000\\P'(x)=2(-0.042)x^1+530x^0-0\\P'(x)=-0.084x+530

This is the marginal profit function , P'.

c)

We need to find P'(4000) and P'(9500). So we basically put "4000" and "9500" in the marginal profit function's "x". The value is shown below:

P'(x)=-0.084x+530\\P'(4000)=-0.084(4000)+530\\P'(4000)=194

and

P'(x)=-0.084x+530\\P'(9500)=-0.084(9500)+530\\P'(9500)=-268

6 0
3 years ago
A survey of 225 students showed the mean number of hours spent studying per week was 20.6 and the standard deviations was 2.7
LekaFEV [45]

Answer:

The margin of error is approximately 0.3

Step-by-step explanation:

The following information has been provided;

The sample size, n =225 students

The sample mean number of hours spent studying per week = 20.6

The standard deviation = 2.7

The question requires us to determine the margin of error that would be associated with a 90% confidence level. In constructing confidence intervals of the population mean, the margin of error is defined as;

The product of the associated z-score and the standard error of the sample mean. The standard error of the sample mean is calculated as;

\frac{sigma}{\sqrt{n} }

where sigma is the standard deviation and n the sample size. The z-score associated with a 90% confidence level, from the given table, is 1.645.

The margin of error is thus;

1.645*\frac{2.7}{\sqrt{225}}=0.2961

Therefore, the margin of error is approximately 0.3

5 0
3 years ago
Read 2 more answers
Which equation best describes the line of best fit?
Andrej [43]
The y-value changes from 10 to 70 as the x-value changes from 0 to 10. That makes the slope (70 -10)/(10 -0) = 6, and the y-intercept = 10.

Selection A is the appropriate equation.
8 0
3 years ago
Please help! due tomorrow
Soloha48 [4]
6v +12 -5v=v +12.
4b +32+2= 4b+34
like that?
5 0
3 years ago
Read 2 more answers
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