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Mumz [18]
3 years ago
12

Are x-1 and 1-x inverse functions ​

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

f5rcrcvtvtvttvg tvfrxrcrc

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09.04 Continuity at a point<br><br> Find the indicated limit, if it exists. (2 points)
LenKa [72]

Answer:

6

Step-by-step explanation:

limit is defined when the limit from both side are defined and equal to f

x-> -10^-, limit f(x)=-4-(-10)=6

f(-10)=6

x-> -10^+, limit f(x)=(-10)+16=6

Then

x->-10, limit f(x)=6

6 0
3 years ago
Find the value of x.
Stells [14]

Answer:

x= 128*

Step-by-step explanation:

180*-52*=128*

6 0
3 years ago
Read 2 more answers
Solve for m <br>5m - 10m = 20<br><br>can anyone help me out?​
sweet-ann [11.9K]

Answer:

m=-4

Step-by-step explanation:

5m-10m=-10m+5m=-(10m-5m)=-5m=20

divide by 5 on both sides, -m=4

miltiply by -1 on both sides, m=-4

8 0
3 years ago
Read 2 more answers
Jim gave 3/8 of his stickers to Hashim and 1/4 of them to Rani. He had 21 stickers left. How many stickers did he have at first?
algol13

Answer:

ten stickers because 24 minus the 4 your friend gave you equals 20. divide that by the number of packs he bought and you get ten stickers per pack.

(10+10+4=20)

Step-by-step explanation:

7 0
3 years ago
What is the following quotient? StartFraction 3 StartRoot 8 EndRoot Over 4 StartRoot 6 EndRoot EndFraction.
Snowcat [4.5K]

You can simplify the given expression by taking out those factors who are perfect squares.

The simplified form  of the given expression will be  \dfrac{\sqrt{3}}{2}

<h3>How to simplify values which are under the root?</h3>

If possible, try to defactor what is inside the root.

For example, if 8 is under square root, then you can defactor 8 as made up of 2 times 2 times 2. Since 2 times 2 is perfect square, thus this can come out of the root.

Simply, some more such methods can be used to simplify these type of values.

<h3>Using the simplification method on given expression</h3>

\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3\sqrt{2 \times 2 \times 2}}{4\sqrt{6}}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}} = \dfrac{3 \times 2\sqrt{2}}{4\sqrt{6}}\\&#10;&#10;\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{6\sqrt{2}}{4\sqrt{6}} = \dfrac{\sqrt{6}\sqrt{2}}{4}\\\\&#10;\dfrac{3\sqrt{8}}{4\sqrt{6}}  = \dfrac{\sqrt{12}}{4} = \dfrac{\sqrt{4 \times 3}}{4} = \dfrac{\sqrt{3}}{2}

Thus, after getting simplified, the expression becomes \dfrac{\sqrt{3}}{2}

Learn more about quotient here:

brainly.com/question/16076853

7 0
2 years ago
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