Please im desperate like actually

A number cube with the numbers 1 through 6 is rolled. What is the probability of the number cube showing an even number or a num

inna [77]

Answer:

Step-by-step explanation:

The correct answer is 5/6 = 83.3%

I really hope this helps!

8 0

3 years ago

(20points + brainlesest) Tom has $10 that he wants to use to buy pens and pencils. however, he does not want to buy more pens an

Nitella [24]

Answer:

Step-by-step explanation:

X<Y

10=3x+Y

7 0

3 years ago

Solve for k. m=−8j−9k+9

inn [45]

Answer: k = -8/9j + -1/9m + 1

Step 1: Flip the equation.−8j − 9k + 9 = m

Step 2: Add -9 to both sides.−8j − 9k + 9 + −9 = m + −9−8j − 9k = m − 9

Step 3: Add 8j to both sides.−8j −9k + 8j = m −9 + 8j−9k = 8j + m −9

Step 4: Divide both sides by -9.
-9k/-9 = 8j + m - 9/-9
k = -8/9j + -1/9m + 1

7 0

3 years ago

Read 2 more answers

A 5-column table with 6 rows titled Number of cans collected. Column 1 has entries 7, 8, 10, 11, 11, 14. Column 2 has entries 16

Reika [66]

The mean is 20 and median is 20 the mode is 15 the range is 36 so that is your answer and hope this helps

5 0

2 years ago

The Pew Forum on Religion and Public Life reported on Dec. 9, 2009, that in a survey of 2003 American adults, 25% said they beli

Nataly [62]

Answer:

The confidence interval at the 99% confidence level for the proportion of all adult Americans who believe in astrology is (0.2251, 0.2749). This means that we are 99% sure that the true proportion of all adult Americans who believe in astrology is in this interval.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$p = 0.25, n = 2003$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.25 - 2.575\sqrt{\frac{0.25*0.75}{2003}} = 0.2251$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.25 + 2.575\sqrt{\frac{0.25*0.75}{2003}} = 0.2749$

The confidence interval at the 99% confidence level for the proportion of all adult Americans who believe in astrology is (0.2251, 0.2749). This means that we are 99% sure that the true proportion of all adult Americans who believe in astrology is in this interval.

6 0

3 years ago