The sum of two consecutive multiples of 10 is 210. find the smaller multiple.
2 answers:
The answer is: " 100 " .
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Explanation:
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10x + 10(x+1) = 210 ; Find "10x" ;
10x + 10x + 10 = 210 ;
20x + 10 = 210 ;
Subtract "10" from each side of the equation;
20x + 10 - 10 = 210 - 10 ;
20x = 200 ;
Divide EACH side of the equation by "20" ; to isolate "x" on one side of the equation; and to solve for "x" ;
20x / 20 = 200 / 20 ;
x = 10
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Solve for "10x"; the smaller multiple;
10x = 10 * x = 10 * 10 = 100 .
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The answer is: " 100 " .
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Guessing but 2x+10=210? Then 2x=200, x=100.
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