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3 years ago

NEED HELP ASAP, WILL GIVE BRAINLIEST

Mathematics

2 answers:

vichka [17]3 years ago

6 0

The answer is converges

zmey [24]3 years ago

3 0

Converges..............

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the first four terms of a geometric progression are 2,10,50,250 a) write down the common ratio of the progression b) write down

VLD [36.1K]

Answer:

The common ratio is 5 and the 5th term is 1250

Step-by-step explanation:

The common ratio is given by

r=U(2)/U (1)

=10/2

The fifth term

U (n)=ar^n-1

U(5)=2(5)^5-1

=2×5^4

=2×625

=1250

3 0

3 years ago

Write the following as an inequality 6 is greater than or equal to x and -2 is less than or equal to x

kipiarov [429]

Answer:

-2 ≤ x ≤ 6

Step-by-step explanation:

The first is ...

6 ≥ x

and it can also be written as ...

x ≤ 6

The second is

-2 ≤ x

The two inequalities can be combined into one compound inequality:

-2 ≤ x ≤ 6

_____

Comment on this answer

I prefer the answer in this form because it puts the parts of the expression in the same order that they appear on a number line. It can also be written as ...

6 ≥ x ≥ -2

7 0

3 years ago

How do I solve this problem 15 = w + 4

vova2212 [387]

Answer:

w = 11

Step-by-step explanation:

Step 1: Subtract 4 from both sides

15 = w + 4

15 - 4 = w + 4 - 4

11 = w

Answer: w = 11

3 0

3 years ago

Read 2 more answers

The revenue from selling x shirts is f(x) = 15x.

Virty [35]

Answer:

p(x) = 8x - 20

Step-by-step explanation:

revenue from selling x shirts is f(x) = 15x

The cost of buying x shirts is c(x) = 7x + 20

p(x) = f(x) - c(x)

To solve this, we need to substitute value of f(x) and c(x) in formula for p(x)

p(x) = f(x) - c(x)

p(x) = 15x -( 7x + 20)

=> p(x) = 15x - 7x -20

=> p(x) = 8x -20

Thus, profit is p(x) = 8x - 20.

3 0

2 years ago

SHOW YOUR WORK, PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

3 0

3 years ago