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-BARSIC- [3]
2 years ago
15

Please can someone help my assignment in math​

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
7 0

Answer/Step-by-step explanation:

1. B = 180 - (90 + 58) (sum of triangles)

B = 32°

Let's find a and b using trigonometric ratios:

Reference angle = 58°

Opposite = a = ?

Hypotenuse = c = 27

Adjacent = b = ?

✔️To find a, apply SOH:

Sin 58 = Opp/Hyp

Sin 58 = a/27

a = 27*Sin 58

a = 22.8972986 ≈ 22.9 (nearest tenth)

✔️To find b, apply CAH:

Cos 58 = Adj/Hyp

Cos 58 = b/27

b = 27*Cos58

b = 14.3 (nearest tenth)

2. B = 180 - (90 + 63) (sum of triangles)

B = 27°

Let's find a and b using trigonometric ratios:

Reference angle = 63°

Opposite = a = 11

Hypotenuse = c = ?

Adjacent = b = ?

✔️To find b, apply TOA:

Tan 63 = Opp/Adj

Tan 63 = 11/b

b = 11/Tan 63

b = 5.6 (nearest tenth)

✔️To find c, apply SOH:

Sin 63 = Opp/Hyp

Sin 63 = 11/c

c = 11/Sin 63

c = 12.3 (nearest tenth)

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6.5yd and 11yd<br> please find the area
Afina-wow [57]
Multiply length times width to find the area. 6.5x11= 71.5
3 0
3 years ago
Researchers at the Centers for Disease Control and Prevention have been studying the decay pattern of a new virus with a decay r
koban [17]

The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

Step-by-step explanation:

The given is,

                     A new virus with a decay rate of 19% per hour  

                    They start with 300 viruses

Step:1

                  Formula to calculate the viruses at decay rate,

                                                  y = A(1-r)^{t}............................(1)

                 Where, y - No of viruses after given time

                             A - Viruses at initial stage

                              r - Decay rate

                              t - No. of hours

                 From the given,

                              A = 300

                               r = 19% per hour

                               t = 7 hours

                Equation (1) becomes,

                                            y = 300(1-0.19)^{7}

                                               = 300(0.81)^{7}

                                               = 300(0.228767)

                                               = 68.63

               Viruses of 7 hours ≅ 69 viruses

                                                     ( or )

Step:1

        For 1st hour,

          = (No.of viruses in hour) - (No,of viruses in last hour × Decay rate )

              = (300)-(300 × 0.19)

              = 300 - 57

              = 243

       For 2nd hour,

              = (243)-(243 × 0.19)

              = 243 - 46.17

              = 196.83

      For 3rd hour,

              = (196.83)-(196.83 × 0.19)

              = 196.83 - 37.39

              = 159.4323

       For 4th hour,

              = (159.4323)-(159.4323 × 0.19)

              = 159.4323 - 30.2921

              = 129.1402

      For 5th hour,

              = (129.1402)-(129.1402 × 0.19)

              = 129.1402 - 24.5366

              = 104.6035

     For 6th hour,

              = ( 104.6035)-( 104.6035 × 0.19)

              =  104.6035 - 19.8747

              = 84.7288

     For 7th hour,

              = (84.7288)-(84.7288 × 0.19)

              =  84.7288 - 16.0984

              = 68.63 viruses

Result:

          The Researcher will find 69 viruses, because 231 viruses are decayed in 7 hours, if a virus with a decay rate of 19% per hour and they start with 300 viruses.

7 0
3 years ago
Factor a2 - 11a + 30
Schach [20]

Answer:

Factor a2 - 11a + 30

A) (6 - a)(5 - a)

B) (a + 2)(a + 15)

<h2><u><em>C) (a + 6)(a + 5) <=YOUR ANSWER</em></u></h2>

D) (a - 6)(a -5)

3 0
3 years ago
Read 2 more answers
Erica likes to ride her horse on a 1/2 mile trail. On Monday, Erica rode her
Mumz [18]

Answer:

21/8 or 2 5/8

Step-by-step explanation:

7/2 miles is equal to 3 1/2 mile trail, or also a 3 2/4 mile trail. You then multiply 3 2/4 and 3/4 and get 2 5/8 or 21/8.

6 0
2 years ago
Drag and drop a statement or reason to each box to complete the proof.
bazaltina [42]

Answer:

1. MN≅QP

  MQ≅NP

2. MP≅MP

3. SSS congruence postulate

4. ∠N≅∠Q

5. CPCTC

Step-by-step explanation:

1. As per the property of parallelogram that opposite sides are congruent, in given case of parallelogram MNPQ the opposite sides

                    MN≅QP  and   MQ≅NP.

2. The reflexive property of congruence states that a line or a geometrical figure is reflection of itself and is congruent to itself. Hence in given case of parallelogram MNPQ

                                         MP≅MP

3. SSS congruence postulate stands for Side-Side-Side congruence postulate, it states that when three adjacent sides of two triangle are congruent then the two triangles are congruent. In given case of parallelogram MNPQ, as the sides MN≅Q, MQ≅NP and MP≅MP hence

                               ΔMQP≅ΔPNM

5. As proven in part 4 that ΔMQP is congruent to ΔPNM, so as per the property of CPCTC (congruent parts of congruent triangles are congruent)

                                 ∠N≅∠Q

5. CPCTC stands for congruent parts of congruent triangles are congruent.

!

6 0
3 years ago
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