Question

Please can someone help my assignment in math​

Answer 1

Answer/Step-by-step explanation:

1. B = 180 - (90 + 58) (sum of triangles)

B = 32°

Let's find a and b using trigonometric ratios:

Reference angle = 58°

Opposite = a = ?

Hypotenuse = c = 27

Adjacent = b = ?

✔️To find a, apply SOH:

Sin 58 = Opp/Hyp

Sin 58 = a/27

a = 27*Sin 58

a = 22.8972986 ≈ 22.9 (nearest tenth)

✔️To find b, apply CAH:

Cos 58 = Adj/Hyp

Cos 58 = b/27

b = 27*Cos58

b = 14.3 (nearest tenth)

2. B = 180 - (90 + 63) (sum of triangles)

B = 27°

Let's find a and b using trigonometric ratios:

Reference angle = 63°

Opposite = a = 11

Hypotenuse = c = ?

Adjacent = b = ?

✔️To find b, apply TOA:

Tan 63 = Opp/Adj

Tan 63 = 11/b

b = 11/Tan 63

b = 5.6 (nearest tenth)

✔️To find c, apply SOH:

Sin 63 = Opp/Hyp

Sin 63 = 11/c

c = 11/Sin 63

c = 12.3 (nearest tenth)