NEED HELP ASAP I will give you Brainly
1 answer:
Both problems are similar, so we can work the general case first.
For ax +by = c, you can solve for y to put the equation into slope-intercept form.
by = -ax +c . . . . . . subtract the x-term
y = (-a/b)x +c/b . .. divide by the coefficient of x
The slope is the x-coefficient, -a/b; the y-intercept is c/b. The function is an odd-degree polynomial function, so its domain and range are both "all real numbers."
2x+3y=18
Slope-intercept form: y = (-2/3)x +6
Domain: all real numbers
Range: all real numbers
Slope: -2/3
Y-intercept: 6
3x-4y > 16
Slope-intercept form: y < (3/4)x -4
Domain: all real numbers
Range: all real numbers
Slope: 3/4
Y-intercept: -4
_____
You will note that the inequality symbol in y < (3/4)x -4 is reversed from that in 3x -4y > 16. That is because in solving for y, we divided by -4. When you multiply or divide an inequality by a negative number, you must reverse the sense of the inequality.
For ax +by = c, you can solve for y to put the equation into slope-intercept form.
by = -ax +c . . . . . . subtract the x-term
y = (-a/b)x +c/b . .. divide by the coefficient of x
The slope is the x-coefficient, -a/b; the y-intercept is c/b. The function is an odd-degree polynomial function, so its domain and range are both "all real numbers."
2x+3y=18
Slope-intercept form: y = (-2/3)x +6
Domain: all real numbers
Range: all real numbers
Slope: -2/3
Y-intercept: 6
3x-4y > 16
Slope-intercept form: y < (3/4)x -4
Domain: all real numbers
Range: all real numbers
Slope: 3/4
Y-intercept: -4
_____
You will note that the inequality symbol in y < (3/4)x -4 is reversed from that in 3x -4y > 16. That is because in solving for y, we divided by -4. When you multiply or divide an inequality by a negative number, you must reverse the sense of the inequality.
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The equation represent a linear relation with the y-intercept
representing the amount of initial fee.
Correct response:
1. 28 volleyball uniforms
2. Price per uniform
3. Initial flat order fee
4. 10 fewer volleyball uniform
<h3>Methods used for finding the above values</h3>The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35
Where;
C = The uniform costs
n = The number of volleyball uniform ordered
The maximum amount the school has to spend = $600
1. The number of uniforms the school can buy is given by setting C = 600 as follows;
- C = 20·n + 35
Therefore;
600 = 20·n + 35
20·n = 600 - 35 = 565
Rounding down to the nearest whole number, we have;
- The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.
2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;
- 20 represents a <u>$20 price per uniform</u>.
3. The 35 in the equation represents an initial <u>flat fee</u>, such as an
ordering or initial fee, which is fixed.
Therefore;
- The number 35 represent the <u>fixed cost </u>for producing the uniforms
4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;
C = 30·n + 35
The number of uniforms the school can by with $600 is therefore;
Which gives;
The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms
The difference in the number of uniforms purchased = 28 - 18 = 10
Therefore;
- The school can purchase <u>10 fewer uniforms</u> at $30 per uniform
Learn more about linear equations here: