6. Often, judging the symmetry and skewness of such distributions is not easy to do by eye, especially when they are asymmetrical or skewed in different ways. Here, the mean of set A is about 7, so the data is skewed to the left more than for set B, which has a mean of about 5.4--closer to the middle of the range.
Both data sets have the same range: 2–10. Set A's mode of 8 is higher than set B's mode of 6.
Hence, the only true statement appears to be
... B. Set B has the lesser mean.
7. For each of the 3 choices of meat, there are 3 choices of bread, and for each of any of those 9 choices, there are 4 choices of condiment—a total of 3×3×4 = 36 choices in all. The best answer is ...
... C. 36
8. The pie chart tells you 5% of the $4800 of monthly income is spent on transportation. That amount is .05×$4800 = ...
... C. $240
The answer is A. Hope that helps
No solution to this problem
The absolute value of y is further from 0.
Explanation:
The absolute value of any number is a positive. If the value of y is greater than x, then y would be further. Let’s input a number as an example. Let’s say that the absolute value of y was 9 and the absolute value of x is 4 due to the y value being larger. 4 is closer to 0 compared to 9 so the absolute value of y is further from 0.
The solution is option D.
0 4
- 6 1
3 -4
Rember rows times columns.
=>
a11 = 4*0 + 0*(-3) = 0
a12 = 4*1 + 0*1 = 4 + 0 = 4
a21 = -1*0 + 2*(-3) = 0 - 6 = -6
a22 = -1*1 + 2*1 = -1 + 2 = 1
a31 = -3*0 + (-1)*(-3) = 0 + 3 = 3
a32 = -3*1 + (-1)*1 = -3 - 1 = -4
