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3 years ago

D) To mix fertilizer correctly. 8

Mathematics

1 answer:

Bas_tet [7]3 years ago

6 0

Start off by making a ratio and write down the given. From there solve and multiply. Hopefully the picture helps :)

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(Two wires with lengths of 48cm and 16cm are to be cut into pieces of all the same length without remainder Find the greatest po

anastassius [24]

The longest length you can get with no extra is 56cm

7 0

3 years ago

Nancy’s morning routine involves getting dressed , eating breakfast, making her bed , and driving to work . Nancy spends 1/3 of

grin007 [14]

Answer: Nancy needs 26 minutes to driving to work.

Explanation:

Since we have given that

Time taken in eating breakfast = 10 minutes

Time taken in making her bed = 5 minutes

Let the total time taken by her in doing routine activities be x

Time taken in getting dressed is given by

$\frac{1}{3}x$

So, According to question,

$\frac{x}{3}+10+5=35\frac{1}{2}\\\\\frac{x}{3}+15=\frac{71}{2}\\\\\frac{x}{3}=\frac{71}{2}-15\\\\\frac{x}{3}=\frac{71-30}{2}=\frac{41}{2}\\\\x=\frac{123}{2}$

Now, we need to find the time taken in driving to work which is given by

$\frac{123}{{2}-\frac{71}{2}=\frac{52}{2}=26\ minutes$

Hence, Nancy needs 26 minutes to driving to work.

6 0

3 years ago

Can someone walk me through how to do this problem please?

Sholpan [36]

Hey!

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We Know:

m∠AED = 34°

m∠EAD = 112°

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Solution:

You notice 4 small triangles in both triangles. That shows that both triangles are the same.

The angles are the same for m∠BDC and m∠AED.

The angles are the same for m∠ADB and m∠EAD

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Angles:

m∠BDC = 34°

m∠ADB = 112°

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Congruent Angles:

m∠AED ≡ m∠BDC

m∠EAD ≡ m∠ADB

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Hope This Helped! Good Luck!

5 0

4 years ago

Help with 2 algebra questions? Will give lots of points too.

Nat2105 [25]

1 b
2 c
Hope it helps:)

3 0

3 years ago

Read 2 more answers

a. Determine all bijections from the {1,2,3} into {a,b,c}. b. Determine all bijections from {1, 2, 3} into {a,b,c,d}.

avanturin [10]

Part A

There are 6 bijections from {1,2,3} to {a,b,c}. This is effectively the same as asking the question "how many ways are there to arrange {a,b,c} where order matters?" We use a factorial to answer this question.

3 factorial = 3! = 3*2*1 = 6

You can also use a permutation, which is composed of factorials, to get the same answer.

======================================================

Part B

There are no bijections from {1,2,3} to {a,b,c,d}. Why is this? Because a bijection has two properties: it must be one-to-one, and it must be onto. The term "onto" in mathematics means "every value in the range is targeted". In the case of the range {a,b,c,d} it is not possible for each value to show up. This is because there are only three items in the domain {1,2,3}. You'll always be one letter short.

As you can probably guess, a bijection is only possible if and only if n(D) = n(R), where D and R are the domain and range respectively. The notation n(D) represents the count or number of items in set D.

3 0

3 years ago