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kotegsom [21]
1 year ago
6

Find the value of x.

Mathematics
1 answer:
hichkok12 [17]1 year ago
8 0
<h3>Angles sum up to:</h3><h3>( n - 2 ) × 180 = ( 5 - 2 ) × 180 = 3 × 180 = 540</h3>

x + 4x + 4x + 135 + 135 = 540

9x + 270 = 540

9x = 540 - 270 \\ 9x = 270

x =  \frac{270}{9}  = 30

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10. Express the following as a single fraction.<br> x-1 +x+2 + x<br>2<br>5<br>4<br>​
Margaret [11]

Answer:

x+x+x=3x

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3x+1

this is ansver

3 0
2 years ago
Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =
vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2

a_1=8

Find the value of a_2

For n=2

a_2=2.9(a_1)-0.2(a_1)^2

a_2=2.9(8)-0.2(8)^2=10.4

Find the value of a_3

For n=3

a_3=2.9(a_2)-0.2(a_2)^2

a_3=2.9(10.4)-0.2(10.4)^2=8.528

For n=4

a_4=2.9(a_3)-0.2(a_3)^2

a_4=2.9(8.528)-0.2(8.528)^2=10.1858

For n=5

a_5=2.9(a_4)-0.2(a_4)^2

a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887

therefore

The population alternates between increasing and decreasing

7 0
3 years ago
Read 2 more answers
Please help!! Math problem and I don't know how to do it!! 14 points!!
IgorLugansk [536]

Let Brian's steps have a measure of 1, and Richard's steps have a measure of k. Then after each walks 5 steps away from the other, their distance apart is

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We are told that distance is equal to 9 of Richard's steps, so is equal to 9k.

... 5 + 5k = 9k

... 5 = 4k . . . . . . . subtract 5k

... 5/4 = k . . . . . . divide by 4

Richard's steps are 5/4 the size of Brian's steps. The appropriate selection is

... b) 5/4

6 0
2 years ago
Sally was the waitress at two tables. At the first table the bill came to $38.70 and the tip was 15%. At the second table the bi
rewona [7]

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{15\% of 38.70}}{\left( \cfrac{15}{100} \right)38.70}\implies \underline{5.805}~\hfill \stackrel{\textit{20\% of 33.45}}{\left( \cfrac{20}{100} \right)33.45}\implies \stackrel{\textit{larger}}{\underline{6.69}} \\\\\\ \stackrel{\textit{by how much?}}{6.69-5.805\implies 0.885}

3 0
3 years ago
Please help with the chart?!?!!?!!?!!?!!?!??!!?!
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Answer:

I'm sorry, I can't really see most of the chart in order to help you. Could you put a zoomed out one instead?

Step-by-step explanation:

The point is to find the average difference or generally "how far each are"

6 0
3 years ago
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