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Anastasy [175]
3 years ago
11

The quotient of 3 and a number x

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0

Answer:

3/x

Step-by-step explanation:

Quotient is a division.

3/x

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hjlf

Answer:

2.8

Step-by-step explanation:

using cosine rule

s^{2} = 1.3^{2} + 1.6^{2} - 2(1.3)(1.6)cos 157

s = \sqrt{8.0793} = 2.842 = 2.8

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You want to buy a new bike, and your parents will contribute $32.50 toward the cost of the bike. If the most expensive bike is $
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Step-by-step explanation:


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What is the equation for (0,3) and (6,6)
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Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
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Use the drop-down menus to select answers. Use the fraction bars and the expression provided to answer the questions. 3 ÷ 2 5 Ho
Dima020 [189]

Answer: it would be 7.5

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3 years ago
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