The total number of digits used when the first 2002 positive even integers are written is 4 digits
<h3>How to find the number of sequence?</h3>
Using arithmetic sequence,
nth term = a + (n - 1)d
where
- a = first term
- d = common difference
- n = number of terms
a = 2
d = 2
nth term = 2 + (2002 - 1)2
nth term = 2 + 4002
nth term = 4004
learn more on sequence here: brainly.com/question/15456604
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Answer:
Step-by-step explanation:
the median is the line inside the box which is 84
Answer:
-6x+12
-9+5a
7x+63
8y-4/5x-12
Step-by-step explanation:
To solve these all you have to do is take the number outside of the parenthesis and multiply them by each term.
-3(2x)-3(-4) All I did here was expand the problem to show what i mean by terms.
-6x+12
Do this for each problem.
0.1(-90)+0.1(50a)
-9+5a
-7(-x)-7(-9) For this one you are taking negatives times negatives so each answer will be positive.
7x+63
4/5(10y)+4/5(-x)+4/5(-15)
8y-4/5x-12
Answer:
the answer is C
Step-by-step explanation:
